-6 -2 9 -11 A = -5 8 -10 11 3 -7 1 let A = Ex: 5 %3|

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A: Let , X→N(μ=9 , σ=2) Our aim is to find the value of x a) P(X&gt;x)=0.5 b) P(X&gt;x)=0.95 c)…

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Q: Which of the following statements is an exponential function? A y=14x+2 (B) y=(6x)² Ⓒ y=(2x+5)3…

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Q: A - [4 = 2 5 5 c=[-³3 C - 1 3 2 3] 0 - 2 1 B = D= 1 5 6 1 0 - 8 2 - 4 5 0 - - 3 1 2

A: Given A=4-1023-2-521, B=15-162-3104, C=51-30 and D=135-10-2 To find-  (a) 5A-3B (b) BD

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Q: P(X) 0. 0.2 1 0.2 0.1 0.5 23

A: We know that, when we have a probability distribution, then to find the standard deviation, we have…

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Q: 6) hln) = 2n-4 gln)%3Dn-2 Find ha) + g(n)

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Q: у (4) + у(3) — 7ӱ —ў + бу %3D 0 у (3) + 3ӱ — 10ў —D 0 -

A: From the given differential equation: (a). y4+y3-7y..-y.+6y=0 So, we can also write as:…

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Q: -1 31 -1 1,D = 3] 1.0 -6 -1 3 Let A = 3 B = C = 3 1 -2 1

A: Topic:- subtraction of matrix

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A: The given problem is to evaluate the given equation and find the value for x. Given equation…

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A: Follow the procedure given below.

Q: T-3 A =| 3 01 -3 4 -9 ol 1. B = l-2 3 1 C =|-2 -2 D = 6 ) 7 10 3 [3 0 F = 0 6 Lo o -3. -4 5 2 20 2…

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Q: d. P(z<-1.32) P(-2.46 < z < 1.74) f. P(1.46 < z< 2.97) g. P(z<1.42)

A: # Z be the standard normal variates then to find probability  P(z&lt;-1.32) P(-2.46&lt;z&lt;1.74)…

Q: Y 1 -1 2 2 -2 -6 3 2 4 3 2 10 3 14 4 7 4 {(4,1) (3, 1)(0, 3)(-7,5)} 2. CO

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Q: -6 3 4. f (x) -5 -1 1

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Q: o f > 0 and f" 0, for a > 3.

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Q: find

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Q: -4 -2 4 -24 -4 (a) f(-1) (b) f(0) (c) f(1) (d) f(1) – f(-1) 2.

A: We have to find

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A:

Q: 1 P(X=x) 0.45 0.35 0.28 -0.12 3. 2.

A: we want to determine  the given probability distribution  x 0 1 2 3 p(X=x) 0.45 0.35 0.28 -0.12…

Q: 0.2x + 0.3y 2 7.5 2.9x - 6.2y s 0

A: Given inequalities are,

Q: X-6 4. h( x) =, V x+1 (а) h(-5) (b) h(-2) (с) h(6) (а) Ҝ10)

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A:

Q: р- 2 a) L f1-7 (v (p – 2)² + 4) 4 b) L-1. (p – 2)² + - 5p2 + P+ 4 (p+ 4)(p² + 4), c) L-1.

A: a) we have to find   L-1p-2p-22+4 we know,  L-1fp-a=eatL-1fp  So, L-1p-2p-22+4=e2tL-1pp2+22…

Q: (1) P(X = 2) P(2 < X < 4).

A: here given ,  Cumulative Distribution of x for Cumulative Distribution  p(X ≤ x) = F(x)

Q: 1. (t. xp- 2x 1 а. 3 /x. + C b. (1+x)³ + C 3 X + C с. 2x(1+x) d. None of the above

A: Given integral is, ∫1+x2xdx.   It is integrated as follows:   ∫1+x2xdx=∫1x+2+xdx

Q: -3 0 5] 1-3 0 5 18) 00 0 1 1 00 0 0 0 A) 5 B) 4 C) 3 D) 2

A: Consider the matrix

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Q: H, ignore my work not sure if it's correct

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Q: f(1 ¹ (1 + 2/1/2) ² du u²

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Q: -2 4t -1 | 29. s = 30. s = t + 1 15(15t – 1)³

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Q: n Compute E 3n-1 n=1 (a) 3/2 (b) )9/4 (c) 2/3 (d) 4/3

A: See solution below

Q: E K N -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 1.) EH = 2.) HN = 3.) KE = 4.) NE = 000

A:

Q: 26. (a) z = 1.98 (b) z -1.89 (c) z 1.65 (d) z = -1.99 -3 /2 7o = 1.96 13 -1.96

A: Rejection rule: If the test statistic is less than –1.96 or greater than 1.96 then reject the null…

Q: (-0.1)-금 (30)+ (150) f-0.1)= 2 3. (-0.1) 3(-0.1) -0.)(120)=683 6. 4

A: Here we have to go back to just previous step were we have function,…

Q: Ex3) 3. 2/3 3. 3. メP。 3. 2. 9. メP 1x3) X-3

A: We make two parts of the integral and integrate them

Q: if E(X) =1 and Var(X)=5, find A) E((2+X)^2) B)Var(4+3X)

A:

Q: Find function of the table.

A: The given table value x y -1 0.5 0 0 1 0.5 2 2 3 4.5 4 8 5 12.5