6) Consider the maternal effect gene that controls snail coiling where D= dextral, dominant, d=sinistral, recessive. Indicate the genotype(s) and phenotype(s) of offspring from the following crosses - females are written on the left, males on the right for each cross. Progeny Genotype(s) (Include ratio) Progeny Phenotype(s) (Include ratio) 1. Dd x Dd 2. dd x Dd 3. Dd x DD 4. Dd x dd

6) Consider the maternal effect gene that controls snail coiling where D= dextral, dominant, d=sinistral, recessive. Indicate the genotype(s) and phenotype(s) of offspring from the following crosses - females are written on the left, males on the right for each cross. Progeny Genotype(s) (Include ratio) Progeny Phenotype(s) (Include ratio) 1. Dd x Dd 2. dd x Dd 3. Dd x DD 4. Dd x dd

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter13: Genes, Chromosomes, And Human Genetics

Section: Chapter Questions

Problem 8TYK: Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene...

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In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene at a different locus is epistatic to the gene for fur color. When present in its dominant W form (WW or Ww), this gene blocks the formation of fur color and all the offspring are white; ww individuals develop normal fur color. What fur colors, and in what proportions, would you expect from the cross AaWw Aa Ww?
A true-breeding rabbit with agouti (mottled, grayish brown) fur crossed with a true-breeding rabbit with chinchilla (silver) fur produces all agouti offspring. A true-breeding chinchilla rabbit crossed with a true-breeding Himalayan rabbit (white fur with pigmented nose, ears, tail, and legs) produces all chinchilla offspring. A true-breeding Himalayan rabbit crossed with a true-breeding albino rabbit produces all Himalayan offspring. Explain the inheritance of the fur colors.
1) By convention, the recessive trait will determine the abbreviation used to track crosses if it is a mutant condition, since it stands out in contrast to the rest of the population. For example, if pea pods are typically green in color, a mutant condition might result in yellow pea pods; therefore, the lowercase letter ‘y’ would be used to depict the mutant state, yellow, while uppercase ‘Y’ would depict the wildtype (wt) condition, green. Remember that the mutant condition is not necessarily always recessive. 1 A) . If green is dominant wt (Y) and yellow is a recessive mutant condition (y), depict a Yy father mated with a YY mother in the Punnett. 1B) Considering the dominant allele, what colors are the parents in the cross above? Yy = _____________________ YY = _____________________ 1C) What colors are the offspring in the cross above? 1D) What is the phenotypic ratio of the offspring? 1E) What is the genotypic ratio of the offspring? (Remember, the genotypic ratio is based…
7. In guinea pigs, black hair colour (B) is dominant and brown hair colour (b) is recessive. Long hair (L) is dominant and short hair (l) is recessive. Answer the following questions: (a) Diagram the cross: BbLl x BbLL (b) What are the phenotypes of the parent generation? (c) What are the genotypes and phenotypes of the F1 generation?
4. An albino corn snake is crossed with a normal-coloredcorn snake. The offspring are all normal-colored.When these first-generation progeny snakes arecrossed among themselves, they produce 32 normalcolored snakes and 10 albino snakes.a. How do you know that only a single gene is responsible for the color differences between these snakes? b. Which of these phenotypes is controlled by thedominant allele?c. A normal-colored female snake is involved in atestcross. This cross produces 10 normal-coloredand 11 albino offspring. What are the genotypes ofthe parents and the offspring?
2. a. A Drosophila male from a true-breeding stockwith scabrous eyes was mated with a female from atrue-breeding stock with javelin bristles. Both scabrous eyes and javelin bristles are autosomal recessive mutant traits. The F1 progeny all had normaleyes and bristles. F1 females from this cross weremated with males with both scabrous eyes andjavelin bristles. Write all the possible phenotypicclasses of the progeny that could be produced from the cross of the F1 females with the scabrous, javelin males, and indicate for each class whether it is arecombinant or parental type.b. The cross in part (a) yielded the following progeny:77 scabrous eyes and normal bristles; 76 wild type(normal eyes and bristles); 74 normal eyes andjavelin bristles; and 73 scabrous eyes and javelinbristles. Are the genes governing these traits likelyto be linked, or do they instead assort independently? Why?c. Suppose you mated the F1 females from the crossin part (a) to wild-type males. Why would thiscross fail…
8. In guinea pigs, the allele for black fur (B) is dominant over the allele for white fur (b). Similarly, the allele for straight hair (H) is dominant over the allele for having rough hair (h). Pure breeding rough haired guinea pigs with black fur were crossed with pure breeding straight haired guinea pigs with white fur. a. State the genotype and the phenotype of the F1 individuals produced as a result of this cross.b. Two F1 offspring were mated together. Calculate the expected ratio of phenotypes in the F2 generation.c. Show the completed Punnett square below.
1. Fur color of rats is determined by the pathway below. The mating between brown rats of identical genotypesproduced the following offspring: 14 cream-colored, 47 Brown, and 19 albino.Gene B Gene DAlbino  Cream  Browna. What type of inheritance is this?b. What is the genotype of the two parents?c. Complete the cross described above. Identify which genotypes are brown, cream, and albino. Includethe expected phenotypic ratio (brown:cream:albino)
1. In a cross between a black and a white guinea pig, all members of the F1 generation are black. The F2 generation is made up of approximately 3/4 black and 1/4 white guinea pigs. (a) Diagram this cross, showing the genotypes and phenotypes. (b) What will the offspring be like if two F2 white guinea pigs are mated?
7. In rabbits, a locus involved in the control of coat colour may be occupied by any of fouralleles: Full colour (C), Sepia (ck), Cream (cd), or Albino (ca). A geneticist counted the numberof Full colour (C), Sepia (ck), Cream (cd) and Albino coat offspring resulting after crossesbetween Sepia (ck) and Cream (cd) coloured coated parents. The results were as follows.• Full colour (C): 152• Sepia (ck): 53• Cream (cd): 39• Albino (ca): 6Mendelian inheritance of this trait predicts that the ratio of Full colour (C) to Sepia (ck) to Cream(cd) to Albino (ca) should be 9:3:3:1. Do the experimental results support this mode ofinheritance?
1. Dihybrid crosses: In dogs, black coat color(B) is dominant to yellow coat fur (b), and straight fur (F) is dominant to curly fur (f). The coat color gene and the fur texture gene are on different chromosomes, so they assort independently, and are not sex linkied. Determine the ratio of having a yellow dog with straight hair if the parents are: BbFF x Bbff a. What are the phenotype of the parents? b. Complete a punnet square. List all the genotypes of the predicted offsprin of this mating c. Based on your Punnet sqaure, list all the genotypes for offspring that would yield a dog with yellow straigh hair d. Based on the punnet square, what is the predicted phenotypic ratio for those parents having a dog with black curly hair.
4. Marfan syndrome is a genetic trait caused by in a dominant allele. The trait causes a weakening of the aorta that can be fatal. A teenager whose mother has the syndrome (but whose maternal grandfather was not affected), and whose father was unaffected, is concerend that she may have the trait. a. What is the phenotype of each of her parents? Genotype? b. What is the chance that the teenager has Marfan syndrome?