(6) Convert 10810 to Binary.
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- •Note: “NOT bits” means flip/invert bits 3) Convert signed decimal to binary dec to bin à bin to 2’s Convert: (-101)10Assume x goes to $s0, y goes to $s1, and z goes to $s2. Convert the following MIPS code to C. addi $s1, $s2, -31. Using 8-bits, convert -45 to excess-127 notation in binary. 2. If 1001 0110 is a binary number in excess-127 form, what is the decimal number? 3. Convert 97 to sign magnitude form using 8 bits. 4. Convert -97 to sign magnitude form using 8 bits. 5. Convert -97 to one’s complement form using 8 bits. 6. Convert -89 to two’s complement form using 8 bits. 7. If 1001 0111 is in two’s complement form, what is the decimal number? 8. Using two’s complement form with 8 bits, perform the following arithmetic. a. Add 34 and 27 b. Add 78 and 64 c. Subtract 45 from 78 d. Subtract -45 from 78 e. Subtract 45 from -78 f. Subtract -45 from -20 9. Convert -123.6875 to IEEE format. 10. Convert 458D A600 from IEEE format to decimal form.
- Java - Convert to Reverse Binary1. two digits 8 & 3, Convert it to a 7-bit binary number (83 → 0010111) 3. Do the analysis of state-tape contents as in diagram (*) in ex.1 for a task of generating parity bit for the number. For the example, initial tape contents should be ΦΦ0010111Φ, and the parity bit is then 0 → final contents on the tape is Φ00010111Φ15. Perform the required conversion from one system to another.4510 to base-16
- (1) Using a 7-bit pattern, calculate the result for the operation (-19+23). Firstly, convert each number to two’s complement. Secondly, calculate the result. Lastly, convert the result back to decimalA(n) _____ operation transforms a 0 bit value to 1 and a 1 bit value to 0.113. The encoding method specified in the EIA-232 standard is _____. a. Differential Manchester b. Manchester c. NRZ-I d. NRZ-L