6 du Consider dx. Transforming the integrand, the result will be where k is a constant. What is u and k? 4+3e* 3 *+ 3, k = - u= 4e X u= 3e +4, k = 3 u= 4e"+3, k = u= 6 e* +1, k = - 3.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.4: Values Of The Trigonometric Functions
Problem 23E
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9.
du
, where k is a constant. What is u and k?
Consider
dx. Transforming the integrand, the result will be K
4+3e
A
u = 4e+3, k =
u= 3e* +4, k = 3
2.
u= 4e+3, k =
3.
D
u= 6 e + 1, k =
23
Transcribed Image Text:9. du , where k is a constant. What is u and k? Consider dx. Transforming the integrand, the result will be K 4+3e A u = 4e+3, k = u= 3e* +4, k = 3 2. u= 4e+3, k = 3. D u= 6 e + 1, k = 23
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