6) Let S be a surface parameterized by: r(u, v) = (u³ + v*)î + (u³ – v³)ĵ+ (2uv)k con u € [0,1], v E [0, 2] A normal vector to S corresponds to: A) N = (6u³ + 6v³)î + (-6u³ + 6v³)ô+ (-18u²v²)k B) N = (6u³ – bv³)î + (6u³ – 6v³)ĵ + (-12u²v²)k C) N = (6u³ – 6v³)î + (6u³ – 6v³)ĵ + (u?v²)k D) N = (6u³ – bv³)î + (-6u³ + 6v³)î+ (u²v²)k

6) Let S be a surface parameterized by: r(u, v) = (u³ + v*)î + (u³ – v³)ĵ+ (2uv)k con u € [0,1], v E [0, 2] A normal vector to S corresponds to: A) N = (6u³ + 6v³)î + (-6u³ + 6v³)ô+ (-18u²v²)k B) N = (6u³ – bv³)î + (6u³ – 6v³)ĵ + (-12u²v²)k C) N = (6u³ – 6v³)î + (6u³ – 6v³)ĵ + (u?v²)k D) N = (6u³ – bv³)î + (-6u³ + 6v³)î+ (u²v²)k

Elementary Linear Algebra (MindTap Course List)

8th Edition

ISBN:9781305658004

Author:Ron Larson

Publisher:Ron Larson

Chapter5: Inner Product Spaces

Section5.2: Inner Product Spaces

Problem 101E: Consider the vectors u=(6,2,4) and v=(1,2,0) from Example 10. Without using Theorem 5.9, show that...

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