6 - What is the basis of the subspace below? W = {(x, y, z)eR³:x + y = 0} {(1,–1,0), (0,0,1)} a) {(1,–1,0), (0,1,0), (0,0,1)} b) {(1,1,0), (0,0,1)} {(1,0,0), (0,1,0), (0,0,1)} {(-1,–1,0), (0,0,1)}

Elementary Linear Algebra (MindTap Course List)
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Chapter4: Vector Spaces
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6 -
What is the basis of the subspace below?
W = {(x, y, z)eR³:x+ y = 0}
{(1,–1,0), (0,0,1)}
a)
{(1,–1,0), (0,1,0), (0,0,1)}
b)
{(1,1,0), (0,0,1)}
{(1,0,0), (0,1,0), (0,0,1)}
d)
{(-1,–1,0), (0,0,1)}
Transcribed Image Text:6 - What is the basis of the subspace below? W = {(x, y, z)eR³:x+ y = 0} {(1,–1,0), (0,0,1)} a) {(1,–1,0), (0,1,0), (0,0,1)} b) {(1,1,0), (0,0,1)} {(1,0,0), (0,1,0), (0,0,1)} d) {(-1,–1,0), (0,0,1)}
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