6. (2y²x−y) dx + x dy = 0

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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QUESTION #6 and #12 please
In Problems 1-6, identify the equation as separable, linear,
exact, or having an integrating factor that is a function of
either x alone or y alone.
1. (2x+yx¯¹) dx + (xy − 1) dy = 0
2.
(2y³ + 2y2) dx + (3y²x + 2xy) dy = 0
3. (2x+y) dx + (x - 2y) dy = 0
(y² + 2xy) dx - x² dy = 0
4.
5. (x²sin x + 4y) dx + x dy = 0
6. (2y²x−y) dx + x dy = 0
In Problems 7-12, solve the equation.
7. (2xy) dx + (y² − 3x²) dy = 0
8.
(3x² + y) dx + (x²y − x) dy = 0
9. (x²-x+y) dx - x dy = 0
10. (2y² + 2y + 4x²) dx + (2xy + x) dy = 0
11. (y² + 2xy) dx − x² dy = 0
12. (2xy³ + 1) dx + (3x²y²-y-¹) dy = 0
I
In Problems 13 and 14, find an integrating factor of the form
x"ym and solve the equation.
13. (2y² - 6xy) dx + (3xy − 4x²) dy = 0
MacBook Air
Transcribed Image Text:In Problems 1-6, identify the equation as separable, linear, exact, or having an integrating factor that is a function of either x alone or y alone. 1. (2x+yx¯¹) dx + (xy − 1) dy = 0 2. (2y³ + 2y2) dx + (3y²x + 2xy) dy = 0 3. (2x+y) dx + (x - 2y) dy = 0 (y² + 2xy) dx - x² dy = 0 4. 5. (x²sin x + 4y) dx + x dy = 0 6. (2y²x−y) dx + x dy = 0 In Problems 7-12, solve the equation. 7. (2xy) dx + (y² − 3x²) dy = 0 8. (3x² + y) dx + (x²y − x) dy = 0 9. (x²-x+y) dx - x dy = 0 10. (2y² + 2y + 4x²) dx + (2xy + x) dy = 0 11. (y² + 2xy) dx − x² dy = 0 12. (2xy³ + 1) dx + (3x²y²-y-¹) dy = 0 I In Problems 13 and 14, find an integrating factor of the form x"ym and solve the equation. 13. (2y² - 6xy) dx + (3xy − 4x²) dy = 0 MacBook Air
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