6. Consider -dx. Transforming the integrand, the result will be k , where k is a constant. What is u and k? 4+3e* 2 u = 6 e +1, k = - A u = 4e*+3, k = 3 u = 3e* +4 , k = 3 u= 4e-+3, k = -

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section: Chapter Questions
Problem 7RE
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Question 19
du
, where k is a constant. What is u and k?
6.
Consider
dx. Transforming the integrand, the result will be k
4+ 3e*
u= 6 e* +1, k = -
3
A
u = 4e*+3, k =
3
B
u = 3e* +4 , k = 3
3
u = 4e -*+3, k = -
2
D
Transcribed Image Text:Question 19 du , where k is a constant. What is u and k? 6. Consider dx. Transforming the integrand, the result will be k 4+ 3e* u= 6 e* +1, k = - 3 A u = 4e*+3, k = 3 B u = 3e* +4 , k = 3 3 u = 4e -*+3, k = - 2 D
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