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6. R(N) is the worst-case running time of sum when called on an ArrayList of size N (and the two blanks are filled in with ArrayList). As part of iii (the explanation of summation), you must state your assumptions about the running time of each ArrayList method (including constructor), with justification.

6. R(N) is the worst-case running time of sum when called on an ArrayList of size N (and the two blanks are filled in with ArrayList). As part of iii (the explanation of summation), you must state your assumptions about the running time of each ArrayList method (including constructor), with justification.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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6. R(N) is the worst-case running time of sum when called on an ArrayList of size N (and the two blanks are filled in with ArrayList). As part of iii (the explanation of summation), you must state your assumptions about the running time of each ArrayList method (including constructor), with justification.
Transcribed Image Text:6. R(N) is the worst-case running time of sum when called on an ArrayList of size N (and the two blanks are filled in with ArrayList). As part of iii (the explanation of summation), you must state your assumptions about the running time of each ArrayList method (including constructor), with justification.
For each problem, please provide Describe the worst-case input (the input that would cause the largest running time) Summation used to calculate number of steps for the worst case Explanation of how the code relates to the summation a. (loops require discussing number of iterations and steps per iteration) b. (recursion requires a diagram) A O bound i. i. ii. iv. static Integer sum(List<Integer> a) { if (a.size() == 0) { return 0; } else if (a.size() == 1) { return a.get(0); } else { a.size()/2; int rightLen = a.size() - leftLen; int leftLen List<Integer> aLeft List<Integer> aRight <>(); <>(); %3D new new %D for (int i=0; i<leftLen; i++) { Integer x = aleft.add(i, x); } for (int i=0; i<rightLen; i++) { Integer x aright.add(i, x); } return sum(aLeft) + sum (aRight); a.get(i); a.get(i+leftLen); %3D
Transcribed Image Text:For each problem, please provide Describe the worst-case input (the input that would cause the largest running time) Summation used to calculate number of steps for the worst case Explanation of how the code relates to the summation a. (loops require discussing number of iterations and steps per iteration) b. (recursion requires a diagram) A O bound i. i. ii. iv. static Integer sum(List<Integer> a) { if (a.size() == 0) { return 0; } else if (a.size() == 1) { return a.get(0); } else { a.size()/2; int rightLen = a.size() - leftLen; int leftLen List<Integer> aLeft List<Integer> aRight <>(); <>(); %3D new new %D for (int i=0; i<leftLen; i++) { Integer x = aleft.add(i, x); } for (int i=0; i<rightLen; i++) { Integer x aright.add(i, x); } return sum(aLeft) + sum (aRight); a.get(i); a.get(i+leftLen); %3D
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