6. Use the definition of the definite integral to evaluate (x - 4) dx. in f(x)dx = lim f(x AX A→0 k=1 = lim E, A. %3D 2+4k n→0 k = 1 a in 2+4k in O B. fox)dx = lim E (x)aX = lim A 0 k= 1 n→00 k = 1 b Oc. fx)dx = lim E(x)ax = lim A→0 k = 1 f(x)dx = 2+ 4k n→0 k= 1 a O D. f(x)dx = lim f(x)AX A 0 k= 1 = lim E n 00 k= 1

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Use the definition of the definite integral to evaluate | (x-4) dx.
2
in
2
Stonik = im E ()a = im E -4:
f(x)dx = lim fx
A→0k=1
O A.
AXK
= lim
%3D
2 + 4k
n-→0k=1
b.
2 +4k
f(x)dx= lim
A→0k=1
= lim E f(x)Ax =
OB.
= lim
%3D
n→0 k = 1
a
Oc. Jrodx = lim E f(x;) ax, = lim E2+
- 4
f(x)dx = lim f(x,)
A→0k= 1
Oc.
4k
n→8k=1
a
b.
4k
2+
n
-4
O D. f(x)dx= lim f(x)AXk
A→0k=1
OD.
= lim >
%3D
n 0 k= 1
Transcribed Image Text:Use the definition of the definite integral to evaluate | (x-4) dx. 2 in 2 Stonik = im E ()a = im E -4: f(x)dx = lim fx A→0k=1 O A. AXK = lim %3D 2 + 4k n-→0k=1 b. 2 +4k f(x)dx= lim A→0k=1 = lim E f(x)Ax = OB. = lim %3D n→0 k = 1 a Oc. Jrodx = lim E f(x;) ax, = lim E2+ - 4 f(x)dx = lim f(x,) A→0k= 1 Oc. 4k n→8k=1 a b. 4k 2+ n -4 O D. f(x)dx= lim f(x)AXk A→0k=1 OD. = lim > %3D n 0 k= 1
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