6. y =√1+√8x-1 y 1$)+ (x-1) ¹4 y'= 1 + 7. y = [(x-1)(2x³ +1)]¹0 8. y = (4x²-1)³ (5x³ + 2)*

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter6: Exponential And Logarithmic Functions
Section: Chapter Questions
Problem 7RE: Does the equation y=2.294e0.654t representcontinuous growth, continuous decay, or neither?Explain.
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Solve problem 5,6,7 and 8

 

Unit 2 Task 2: Chain Rule
1. y = (4x² - 1)*
y² 4 (4x²-1)³ · (8x)
"y: 32x(4x²-1)³²
2. y = (3x + x² +10)³
y 3(3x+x²+10)
(12x²+2x)
y' = (36x³ +6x) (3x² +22² +10)²
Differentiate each function. You are not required to simplify.
3.
yet (52²-7x) * ½ x (10x-7) *(10x-7)
y' = 102-7
4. y=√x³-2x
y²=56²³-4=23²³ 3
y' = x ² = 2x² ³.
-
5. y=[(x²-3x)*+*²³
6. y =√1+√8x-1
y 1²) + (x-1)
y'= 1 +
7. y=[(x - 1)(2x³ + 1)]¹⁰
8. y = (4x²-1)³ (5x³ + 2)*
و من
2x3
Transcribed Image Text:Unit 2 Task 2: Chain Rule 1. y = (4x² - 1)* y² 4 (4x²-1)³ · (8x) "y: 32x(4x²-1)³² 2. y = (3x + x² +10)³ y 3(3x+x²+10) (12x²+2x) y' = (36x³ +6x) (3x² +22² +10)² Differentiate each function. You are not required to simplify. 3. yet (52²-7x) * ½ x (10x-7) *(10x-7) y' = 102-7 4. y=√x³-2x y²=56²³-4=23²³ 3 y' = x ² = 2x² ³. - 5. y=[(x²-3x)*+*²³ 6. y =√1+√8x-1 y 1²) + (x-1) y'= 1 + 7. y=[(x - 1)(2x³ + 1)]¹⁰ 8. y = (4x²-1)³ (5x³ + 2)* و من 2x3
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