6-13 A:A-36 sla s- resl bass 100mmm IND: AM aximurn mormad m tm 125 SOLUTTON Replace A-6 wih bmss 2001.9802 I0I GPa All basg: 1.0

Q: P. = 30KN Pz = 20KN 4m a = 1 L = 6m R2

A: Let R1=RAR2=RBRA+RB=50KN∑MA=030×1+20×5-6RB=0RB=21.666 KNRA=28.334 KN

Q: Ec Eb ea 30° ----

A: Strain rosette given we know the direct result so we can proceed

Q: Chupter Tuu Forve Sydem 4-37. Determine the resultant force and specify where it acts on the beam…

A: As per guidelines we are supposed to answer only first question so please repost rest questions…

Q: Describe the following   i) BCP-SP-07 ii) ACI-318

A: i) BCP-SP-07  : This ia building code of pakistan  to design structures under seismic…

Q: For the beam shown, EI = 24 × 10° kip-in² over the length of the beam. The slope (rad) of the beam…

A:

Q: a)      Describe the following   i) BCP-SP-07 ii) ACI-318 . Subject: RCD 2

A: Let us describe  BCP-SP-07 and ACI-318 in step 2.

Q: Problem 1.8 - Express the 260-N force in terms of components and parallel to the inclined plane…

A: As multiple questions are asked and as per the guideline only very first question will be…

Q: Censistentdefor. Ex5n Analyze the frame shown. method Cassume re dundants are using Cx cund Cy) GL…

A: Method of Consistent Deformations (Flexibility Method): Consider the free body diagram of the given…

Q: M- 12 (25L - 40L2x2 + 16x*) Ely- 960L WL SwL 192EI WoL -8,- WL 120EI 60EI for 0<x < 6. ML L.

A: Find maximum deflection of given beam

Q: Determine the location (x̄, y̅) of the centroid C of the area.

A: Consider the following diagrams for calculating the centroid C of the area:

Q: RD RA R. = 40 KN VD1² VD2 = M B1 82 2 m Mg2 MB1 hinge t-4m. Vpz KN KN 2 kN/m KN KN KN KN kNm kNm kNm…

A:

Q: 40 kN 20 kN 20 kN A IAB = 120(10°) mmB IBC = 90(10°) mm1[C -3 m- -3 m-3 m- -4 m -4 m s ai 8 omuazA…

A:

Q: Sample ID NazSO4 solution (%) MGSO4 solution (%) Na2SO4+M9SO4 solution (%) ОРС -30 -21 -35 OPC÷FA…

A:

Q: 1. Match the Following: 1) M = (6lx - 6x - P) 12 5F MAB =(11x- 3I) 16 MBC R1 R. 16 F Wx M =(1- x) R1…

A:

Q: GENERAL LOAD 4m A B 20kN H 30kN 20kN C G 30kN 4 @ 3m 12m 20kN 30kN E A = 1000mm² E = 200 GPa

A:

Q: Ans. 2ET 60L I8 T8O Fig. 821 Fg. 822

A:

Q: 50, 75, 75, 75 50 AHA H W310x60 Calculate the maximum A36 Fy = 250, Fu = 400 service dead and live…

A:

Q: Px :(3L – x) 6EI PL Px PL? (3L² - 4x) osxs 48EI 3EI 2EI Phx Px2 (L² - -) 6LEI (3a - x) 0sxsa 6EI Pa…

A:

Q: 7nter-ahラ% #3-A water tank is 10m n diameter ard 1am high. if the tark is to be IS 10m m completely…

A:

Q: GN ,6N Actual Beam 1a5mr 12S mm 125mm Soamm 6N 6N Puimay stnctine AB By = IN By Redundant lathlied…

A:

Q: Draw the shear and moment diagrams for the beam.

A:

Q: A cantilever beam shown in Fig , with rectangular section shown. Its carry uniform load wand…

A:

Q: fl m→ -2.0 m- e total deflection at B. [Hint: Use

A: a)   Take , a = 1m from left  , x = 2m from left , l = total length = 4m Given : EI = 2000 KNm2…

Q: M(red bending) Sation Raaye D -o- 125 ongin -0. CE 622 BE -0-125 フュナロ125 -o.125+X3-0-37543 -2.1+ 6メ3…

A: Yes, the table is correct. If you have any other queries please feel free to ask.

Q: Ias 글 RAz2-Mo (z-블〉 + Ci, Ely = Mo B –L/2- -L/2– = 59kNm. L = 12m ine the EI0 at point A

A:

Q: B• 400 Turget -7-

A:

Q: Design a simply supported rectangular reinforced concrete beam. Fy 400MPA „Fc 30 MPa ,Bar dia= 25 No…

A: Calculating the self-weightγc×b×h of beam: W=γc×b×h     =24*0.6*0.325     =4.68 KN/m The factored…

Q: Cantilever method |ookN- 3. SM 200KN J + इम 6 sm 8m H IL

A:

Q: Given the following: b=350mm d=550mm fc'=35MPA fy=420MPA Mu=700KN-m Determine As USE NSCP 2015, As =…

A:

Q: B2-8m RC Beem Sec B-B Sec A-A C1 (0.8x0.8)m Sec A- Sec A-A Sec A- Sec 8-B 143.9* Sec A-A Sec A- -…

A: Solution: To find the length of the beam B1, B2 &amp; B3 Already for beam 2 and 3 length was shown…

Q: 1. Show that: GE (a) k = 9G-3E 3k-2G (b) v = 6k+2G

A:

Q: =515mm E'=25MPA =320MPA lu=420KN-m etermine As USE NSCP 2015, As = || sq.mm.

A: Given:- b=305mm d=515mm f'c=25MPa fy=320MPa Mu=420kNm To find:- a)NSCP2015-As b)NSCP 2001-As

Q: 4-13. Design stirrups for the beam shown. The supports are 12-in. wide, and the loads shown are…

A:

Q: h 10mmp 9-28mm fc' = 23.3 MPa fy = 422.4 MPa bw = 302 mm h = 357 mm be 00 2-1Commo food 15 ootd bw…

A: Hi! Thank you for the question As per the honor code, We’ll answer the first question since the…

Q: Given the following: b=355mm d=575mm fc'=27.5MPA fy=275MPA Mu=670kN-m Determine As A. USE NSCP 2015,…

A:

Q: D= 265k L = 130k a. Select a W16 of A992 steel. Use the trial-and-error approach. 1. Use LRFD. 2.…

A: Given : - Dead Load = 265 K Live Load  = 130 K  Length = 18'  Use W 16 steel

Q: b=480mm d=700mm fc'=30MPA fy=400MPA Mu=1430kN-m Determine As A. USE NSCP 2015, As = sq.mm. B. USE…

A:

Q: PoL=280* PL= 200k Please select the ligutest W12 A992 steel

A: Column: Structural columns are components that span the entire altitude of the structure as well as…

Q: OF THE STEEL FRAME SU PPORT BUILOING SSHOWN BELW 3. A FLAT Roof I6 INTEDED To A LIE LOAD DF 1.9 KPa…

A: Slab: A slab is a structural element that is constructed to create a flat and horizontal surface.…

Q: Draw influece line for Rvd (Please focus on the solution process) P=1 Hinge P RvD A اد* - 4m a 13 C…

A:

Q: 3) In= 24-0" SIMPLY 8'-0" TYP SUPPORTED Kー 5000 psi %3D 29.5" ィ= 6o Ksi WOL= 1.25 KLF 3-#9 CHECK Et…

A: Answer We are given  Beam span = 24 ft f'c =5000 psi fy = 60 ksi Dead Load WDL = 1.25 K/ft Effective…

Q: Lecturer. Mohammed Abdul-Jabbar Hassan. Reinforced concrete for third stage of Civil Engineering.…

A: Given:  As=4000mm2 Effective Cover =75mm fc=25Mpa fy=400Mpa d=500mm b=300mm   To Find:  Maximum…

Q: Q#2 b)Describe the following i) BCP-SP-07 ii) ACI-318

A: (i) Newly developed building code of Pakistan – seismic Provisions 2007 (BCP-SP 07). detailed…

Q: Design a retangulan Column with a width of l4" given: =150k; PL=200k MD=D100ftk ML 00k-ft fle=Akei;…

A: Width of column = 14" (given) Pu (factored load) 1.2dead load + 1.6 live load area  of steel  = 0.8%…

Q: Ans. ốc - PL U2 L/2 Anc I 48EI PLU4 M- diag

A:

Q: 2. Investigate the adequacy of member BF (L 100 x 100 x 13 mm) shown. Fy 248 MPa, Fu = 400 MPa. Use…

A: The beam is a very useful structure in the building. It transfers the load from the uppermost part…

Q: 25 kN/m m- 15 kN 15 kN 15 kN B -6m- e follow instructions and provide plete answers and solutions.…

A:

Q: PReBLOm I FLAT BAR tf FLAT BAR X-AYIS tw 15mm tp = to FLAT BAR 19omm RegOIRED De TERMINE THE…

A: Given:- To find:- Properties of the built-up section:_

Unit Conversion

Standard units are also called SI units. SI units are used for measuring a physical quantity satisfying certain conditions. There are two types of units: fundamental units and derived units. Fundamental units are physical quantities that are independent, that is, they do not depend on other quantities like mass, length, or time. There are plenty of quantities in our lives which need to be measured and compared. Measuring is the comparison of a particular physical quantity with its reference value. A unit is a measure of a fixed physical quantity. A physical quantity is the product of a unit and the numerical value we need to compare with.