write TRUE in the space provided if the statement is correct and FALSE if incorrect. write your solution. Vx² +64dxsec' ede6.2tan e7. In x25 +x dx, we let x=5 tan e.S. In | x.-625 dx, if we let x= 25sece, thendx= 25sece de.9. The result of the integral in 6, given25dx is 5 tan e- 50 + C.10 (x/49-x² dx when converted to e is 7 sine cos e de.211. To each linear factor occurring once in the denominator of a proper fraction,Adxthere corresponds a single partial fraction of the formwhere A isax+bconstant and to be determined.(4x +5x*)dx(x+1)(x2 -6x +34)212. By the method of partial fractions, the integralcan beAB(2x - 6)evaluated when expressed asdx .x+1(x2 - 6x + 34)2(3x² +8x –12)kixx + 7x +12x13. Inthe complete factored form of the denominator isx(x+ 4)(x+ 3)

Answered: Image /qna-images/answer/10e71800-f310-40ce-a2ab-e5de7e8773a5.jpg

Answered: + 64dx x² sec' ede 6. tan ?e 7. In…

+ 64dx x² sec' ede 6. tan ?e 7. In [x/25+ x² dx, we let x= 5 tan e. S. In xx-625 dx, if we let x 25sece, thendx=25sece de.

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter4: Calculating The Derivative

Section4.4: Derivatives Of Exponential Functions

Problem 37E: Use graphical differentiation to verify that ddxex=ex.

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write TRUE in the space provided if the statement is correct and FALSE if incorrect. write your solution.

Vx² +64dx
sec' ede
6.
2
tan e
7. In x25 +x dx, we let x=5 tan e.
S. In | x.
-625 dx, if we let x= 25sece, thendx= 25sece de.
9. The result of the integral in 6, given
25
dx is 5 tan e- 50 + C.
10 (x/49-x² dx when converted to e is 7 sin
e cos e de.
2
11. To each linear factor occurring once in the denominator of a proper fraction,
Adx
there corresponds a single partial fraction of the form
where A is
ax+b
constant and to be determined.
(4x +5x*)dx
(x+1)(x2 -6x +34)2
12. By the method of partial fractions, the integral
can be
A
B(2x - 6)
evaluated when expressed as
dx .
x+1
(x2 - 6x + 34)2
(3x² +8x –12)kix
x + 7x +12x
13. In
the complete factored form of the denominator is
x(x+ 4)(x+ 3)

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