The question asks for you to use the chain rule to solve. Problems 67 and 69Thanks! 3x+9)-4/3 20mu+41)+ sin x67. y = (2e³x + 3e-2x)4aughisted69. y = e(x²+2x+3)²SECTION71. y =√√1+√1+√x73. y = (kx + b)-1/3; k and b cons1√kt4 + bIn Exercises 75-78, compute the higd²75. sin(x²)dx²74. y ==;k and b consta

Answered: 67. y = (2e³x + 3e-2x)4

Math

Calculus

67. y = (2e³x + 3e-2x)4

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter4: Polynomial And Rational Functions

Section4.4: Complex And Rational Zeros Of Polynomials

Problem 14E

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Question

The question asks for you to use the chain rule to solve. Problems 67 and 69 Thanks!

3x+9)-4/3 20
mu
+41)
+ sin x
67. y = (2e³x + 3e-2x)4
aughisted
69. y = e(x²+2x+3)²
SECTION
71. y =
√√1+√1+√x
73. y = (kx + b)-1/3; k and b cons
1
√kt4 + b
In Exercises 75-78, compute the hig
d²
75. sin(x²)
dx²
74. y =
=;k and b consta

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