- (6+j7) – 10 cjs 30° + 10ej0.752 + 5Z–25° (3+j4) + 5 cjs 45° + 5 2–45° = 6-jx +r Z 10° what is r and x? (A ·C) / B – B/(A+ B) ; A = 34 5° ; B = 4–j5; C = 3 cjs 30°

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A: We have to solve one question as per guideline Please repost other question again

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A: Check by points

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A: This question belongs to derivative of inverse trigonometric function.

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