6x Evaluate the indefinite integral. 6e sin (e) dæ U = du 9e9x dx %3D Substitution gives du Integration yields The final answer is

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A: ∫9e9xe9x+45dx=9·∫e9xe9x+45dxLet u=e9x+4.So, du = 9e9x.=∫99u5du=∫1u5du

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