7-12 - Triangular Systems Use back-substitution to solve the triangular system. x - 3y + z = (3x – 3y + z = 0 y - : = 3 := -2 7. 8. y + 4z = 10 2= 3 x + 2y + z = 7 2y + 3z = 10 x – 9. -y + 3z = 9 10. 2y - z= 2 2z = 6 3z = 12 (2r – y + 6z = 5 y + 4z = 0 4x + 3z = 10 11. 12. 2y - := -6 -2z = 1 4

7-12 - Triangular Systems Use back-substitution to solve the triangular system. x - 3y + z = (3x – 3y + z = 0 y - : = 3 := -2 7. 8. y + 4z = 10 2= 3 x + 2y + z = 7 2y + 3z = 10 x – 9. -y + 3z = 9 10. 2y - z= 2 2z = 6 3z = 12 (2r – y + 6z = 5 y + 4z = 0 4x + 3z = 10 11. 12. 2y - := -6 -2z = 1 4

College Algebra

7th Edition

ISBN:9781305115545

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter5: Systems Of Equations And Inequalities

Section5.2: Systems Of Linear Equations In Several Variables

Problem 11E: Triangular system Use back substitution to solve the triangular system {2xy+6z=5y+4z=02z=1}

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