7 In an RLC circult, assume wn and wn such that I(jon) = I(joz) = Imux//2 and Aw such that Aw = w2 – w1. In other words, Aw is the width of the current curve where the current has fallen to 1//2 = 0.707 of its maximum value at the resonance frequency. At these frequencies, the power dissipated in a resistance becomes one-half of the dissipated power at the resonance frequency (they are called the half-power points). In an RLC circuit with a high quality factor, show that Q= wo/Aw.

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7 In an RLC circult, assume wn and wn such that
I(jon) = I(joz) = Imux//2 and Aw such that
Aw = w2 – w1. In other words, Aw is the width of the
current curve where the current has fallen to
1//2 = 0.707 of its maximum value at the resonance
frequency. At these frequencies, the power dissipated
in a resistance becomes one-half of the dissipated
power at the resonance frequency (they are called the
half-power points). In an RLC circuit with a high
quality factor, show that Q= wo/Aw.
Transcribed Image Text:7 In an RLC circult, assume wn and wn such that I(jon) = I(joz) = Imux//2 and Aw such that Aw = w2 – w1. In other words, Aw is the width of the current curve where the current has fallen to 1//2 = 0.707 of its maximum value at the resonance frequency. At these frequencies, the power dissipated in a resistance becomes one-half of the dissipated power at the resonance frequency (they are called the half-power points). In an RLC circuit with a high quality factor, show that Q= wo/Aw.
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