2 cot 4x = cot 2x – tan 2x

Q: tan 0 + tan? 0 = sec* 0 - sec² 0

A: This question is taken from trigonometry in which we have to prove the given identity  We can write…

Q: Solve If tan 0 = -4.5, find the value of tan 0 + tan (0 + T) + tan (0 21).

A:

Q: d 1 dr tan? (x)

A:

Q: 12 tan(0) = find sec(0) 12

A: sec(theta)=? cos(theta) = ?

Q: 3 sin? 0 4 2 %3D

A:

Q: у %3D Сi tan4x — 5С2 sec4x |

A:

Q: cos? 0 – sin? 0 =1 cotx sec x = csc x

A: we have to prove that the given statements are true or false: (i)cos2θ-sin2θ=1 (ii)cotx secx=cscx

Q: 20 Y 2. Sin X 15 25

A:

Q: (3sin(0.3)) + cos(tan-(4.9))

A: put calculator in radian mode. 0.88656+0.19996=1.086 ans :d

Q: tan x+ cot x) dx

A: Recall trigonometric identities, Substituting the values in above equation, we get

Q: (a) tan 1 1 (b) cos (c) tan (tan 577) (d) cos(tan(-V3))

A:

Q: 21 and tan(0) 29 21 find sec(0). 20 If sin(0)

A: To.find - Value of sec theta.

Q: /24 x tan? (6x) dx = sin(5x) %3D

A: Consider the integral  ∫0π/24xtan26xdx

Q: tan(x+1) Find y' of y =

A: y=tanx+1x

Q: Establish each identity.

A: Given: L.H.S=tanθ+cotθ We can write it as, tanθ+cotθ=sinθcosθ+cosθsinθ=sin2θ+cos2θsinθcosθ=1sinθcosθ

Q: Establish each identity.

A: Given: The statement secθ-cosθ=sinθtanθ, To find: The given identity.

Q: 3. tan r dr cos r 6.

A: Given: To find: The value of the integral.

Q: 1) 2 cot 2x = cotx-tanx

A:

Q: 9. у %3D 4sin' (2xх) 10.у %3D tan? (x3) 11.у %3D sec(-х2 + 3х — 4)3

A: Question 9,Given,          y=4sin32x

Q: sec 0 – cos 0 = sin 0 tan 0

A:

Q: 3 sin(0) = 8. find cot(0)

A: We will use trigonometric identity Sin2(x)+cos2(x)=1.

Q: tan (x) sec" (x)dæ

A:

Q: et sin x | lim x → 0 18 cos x 18 (Use calculator and write your final answer in the given box)

A:

Q: 5 [cot 0 · sec 0 · sin 0]

A: Given: 5cotθ·secθ·sinθ

Q: 4 sin e = cos 0 = tan 6 = csc e sec e cot 0 = 3.

A: The values are:

Q: 1 1 sec2 x+cot2 x csc2 x+tan? x ||

A:

Q: 2 tan? x + 4 tan x – 3 = 0 (3 sin 2x - = 0

A:

Q: 1+tan^2x+sec^2xcot^2x/csc^2x+cot^2xcsc^2

A: we have to solve the given trigonometry equation,  1+tan22x+sec22x cot22xcsc22x+cot22x csc22x

Q: 2. a. arctan(-1) b. tanV3 C. tan-

A: a)tan-1(-1)=-π4b)tan-1(3)=π3

Q: Evaluate the integral.

A:

Q: tan x+ cot x csc(2x) = %3D

A:

Q: cot'x 3 10. cscxcotx %3D secxtanx %3D

A: Given equation :

Q: 9. sin cot x. xo a

A: According to our guide we can attempt only one question so i am providing answer for 1st question .

Q: 2人 x = 6 sin? 2y

A: The given equation is Now, we have to show that,

Q: 3 (cos x)2 + 2 2(cot x)3 +4 cot x-5

A: Given the integral ∫3(cosx)2+22(cotx)3+4cotx-5dx

Q: _1 3 tan2 0+ cot 0 3D2

A:

Q: sin[cos^-1(12/13)+tan^-1(4/3)]

A: Given:

Q: 3. cot cos h. csc 2 tan i. sin(sec x) g. 12

A:

Q: 5. tan?x = 3 secx 2 %3D

A: As per our guidelines we are supposed to answer only one question. Kindly repost others question as…

Q: 4. Simplify the expression an+cot - sec²x O-tan² x Osec² x tan²x

A:

Q: 4 tan 0+ tan? e-3 14) 3 cot* 0+11 cot? 0 – 4 15) 3 csc? 0 - 4 sec? 0

A: Given: 14)  4tan4θ+tan2θ−3sec2θ15)  3cot4θ+11cot2θ−43csc2θ−4

Q: sec? ede 2. tan' 0+9 tan e

A:

Q: (V3 + 1)(3– cot30°) tan60° - 2 sin 60°

A:

Q: cos ydy Sin y+ 5 sin 3 sin y+6

A: Since you have asked multiple questions in single request  so we  will be answering only first…

Q: If y= tan (kx) + tanh'(kx) and (1 - 625 x) y'=A Then K=, -.... Answer:

A:

Q: 32. tan?x sec x dx 7/2 35. cot'x dx

A: Topic :- Integration

Q: tan? x - cot2 x = sec? x- csc² x %D

A:

Q: tan? x 1. Simplify: - 1+secx 2. Simplify: cot? x (sin² x)

A: Using trigonometry, we can solve these problems

Q: 4) cot 0 + tan 0 = sec 0 csc 0

A: To prove  cot(theta)+tan(theta)=sec(theta)csc(theta)