7. Consider the indefinite integral J Then the integrand has partial fractions decomposition 6x+6x²+48x+64 xp: x4+16x2 a сх + d x2 where x2 + 16 a = b = C = d = Integrating term by term, we obtain that 6x3 + 6x2 + 48x + 64 -dx = x4 + 16x2

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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7. Consider the indefinite integral J
6x+6x²+48x+64
xp:
x4+16x2
Then the integrand has partial fractions decomposition
a
сх + d
+-+
x2
x2 + 16
where
a =
C =
d =
Integrating term by term, we obtain that
6x3 + 6x² + 48x + 64
dx%3D
x4 + 16x2
Il I II
Transcribed Image Text:7. Consider the indefinite integral J 6x+6x²+48x+64 xp: x4+16x2 Then the integrand has partial fractions decomposition a сх + d +-+ x2 x2 + 16 where a = C = d = Integrating term by term, we obtain that 6x3 + 6x² + 48x + 64 dx%3D x4 + 16x2 Il I II
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