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- 10. public static void methodl (int i, int num) { for (int j = 1; j <= i; j++) { " "); System.out.print (num + num *= 2; } System.out.println(); } public static void main(String[] args) { int i = 1; while (i <= 6) { methodl (i, 2); i++; }public static void main(String[] args) { int a; int b; int c; c = quad(0,1, 2); b = quad(1, 2, 3); a = quad(5, 6, 7); c = c +b+ a; } private static int quad(int a, int b, int c) { int r; r= a +b+ c; return r; } For the code above, how many entries does the activation record for method quad have? During the execution of main, at most how many activation records are existent on the run-time stack?Input class ternary_operator { public static void main(String args[]) { int x = 3; int y = ~ x; int z; z = x > y ? x : y; System.out.print(z); } } Find output
- Given the following: #includ int a[] ={4, 6}, i = 0, y =3, z =1; void f(int x){ int z = 2; g (); X = x + y; z = z +X; i++; return x + a[ i ]+y; } void g(){ z += 3; y = a[i] + z; } void main(){ printf("%d", y + f( a[i] ) - y); } State the output assuming the following: A) Call by reference, dynamic scoping, operands are evaluated right to left. B) Call by name, static scoping; operands are evaluated left to right.class overload { int x; double y; void add(int a , int b) { x = a + b; } void add(double c , double d) { y = c + d; } overload() { this.x 0; %3D this.y = 0; } %3D } class Overload_methods { public static void main(String args[]) { overload obj int a = 2; double b - 3.2; obj.add(a, a); obj.add(b, b); System.out.println(obj.x + } = new overload(); + obj.y); } #3Run the codeclass operators { public static void main(String args[]) { int x = 8; System.out.println(++x * 3 + " " + x); } } Give result for the code Java Try to do ASAP ?
- class TenNums {private: int *p; public: TenNums() { p = new int[10]; for (int i = 0; i < 10; i++) p[i] = i; } void display() { for (int i = 0; i < 10; i++) cout << p[i] << " "; }};int main() { TenNums a; a.display(); TenNums b = a; b.display(); return 0;} Continuing from Question 4, let's say I added the following overloaded operator method to the class. Which statement will invoke this method? TenNums TenNums::operator+(const TenNums& b) { TenNums o; for (int i = 0; i < 10; i++) o.p[i] = p[i] + b.p [i]; return o;} Group of answer choices TenNums a; TenNums b = a; TenNums c = a + b; TenNums c = a.add(b);class TenNums {private: int *p; public: TenNums() { p = new int[10]; for (int i = 0; i < 10; i++) p[i] = i; } void display() { for (int i = 0; i < 10; i++) cout << p[i] << " "; }};int main() { TenNums a; a.display(); TenNums b = a; b.display(); return 0;} Write a copy constructor for the above class TenNums. Make sure it performs deep copy. Group of answer choices TenNums(const TenNums& b) { p = b.p;} TenNums(const TenNums& b) { p = new int[10]; for (int i = 0; i < 10; i++) p[i] = b.p[i];} TenNums(const TenNums b) { p = new int[10]; for (int i = 0; i < 10; i++) p[i] = b.p[i];} TenNums(const TenNums b) { p = b.p;}class main { public static void main(String args[]) { int x =2; int y =0; for(; y <10;++y) { if(y % x ==0) continue; elseif(y ==8) break; else System.out.print(y +" "); } } } Give result for the code Java Try to do ASAP
- class class { public static void main(String args[]) { int a =5; int b =10; first: { second: { third: { if(a == b >>1) break second; } System.out.println(a); } System.out.println(b); } } } Give result for the code Java Try to do ASAP#include int main() { for(int i=1;i<8;i++) { if(i % 2 == 1) { for (int j=1;j<=i;j++){ printf("%d",i); } printf("\n"); } } return 0;Explain this java codes private void put(int cell,int player) { int i=-1,j=-1;; switch(cell) { case 1:i=2;j=0;break; case 2:i=2;j=1;break; case 3:i=2;j=2;break; case 4:i=1;j=0;break; case 5:i=1;j=1;break; case 6:i=1;j=2;break; case 7:i=0;j=0;break; case 8:i=0;j=1;break; case 9:i=0;j=2;break; default:display(overridegrid);return; } char mark='x'; if(player==0) mark='o'; grid[i][j]=mark; display(grid); } private int startGame() { init(); display(grid); int status=playingid; while(status==playingid) { put(playerMove(),0); if(override==1) { System.out.println("O wins."); return playerid; } status=checkForWin(); if(status!=playingid) break; try{Thread.sleep(1000);}catch(Exception e){System.out.print(e.getMessage());} put(compMove(),1); status=checkForWin(); } return status; } private void init() { movesPlayer=""; override=0; marks=new int[8][6]; wins=new int[][] //new int[8][3]; weights=new int[]{3,2,3,2,4,2,3,2,3}; grid=new…