Question
Asked Sep 16, 2019

Find voltage and currents across each resistor

70
to n
Cofrent Flow
бол
SV
Fn
Val tage and (ulrent acl0ss
cach resistor
V
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70 to n Cofrent Flow бол SV Fn Val tage and (ulrent acl0ss cach resistor V

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check_circleExpert Solution
Step 1

First, calculate the value of equivalent resistance.

70x8037.330
R10/8070+80
In series with 9OS2
R3733-90 37.333+90 127.330
3000 27.27
50x 60
R50,60 50+60
110
127.33x27.27 3472.28922.452
=
12733 2ו
154.6
127.33+27.27
R22 45+40 = 22.45+40 = 62.45
20x30 60- 122
R2030 20+30
50
62.45x12 749.4 10.062
R245126245+12
74.45
R006-10 10.06+ 10 = 20.06
5V
20.060
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70x8037.330 R10/8070+80 In series with 9OS2 R3733-90 37.333+90 127.330 3000 27.27 50x 60 R50,60 50+60 110 127.33x27.27 3472.28922.452 = 12733 2ו 154.6 127.33+27.27 R22 45+40 = 22.45+40 = 62.45 20x30 60- 122 R2030 20+30 50 62.45x12 749.4 10.062 R245126245+12 74.45 R006-10 10.06+ 10 = 20.06 5V 20.060

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Step 2

The amount of current and voltage through 10Ω resistor will be

5
=0.25A
Ioa 20.06
V100 = 0.25Ax10n=2.5V
Modified circuit
10Ω
402
37.330
5V
|120
90Ω
27.27Q
WW
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5 =0.25A Ioa 20.06 V100 = 0.25Ax10n=2.5V Modified circuit 10Ω 402 37.330 5V |120 90Ω 27.27Q WW

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Step 3

Applying Kirchhoff’s Voltage...

10Ω
+2.5V
5V
+
120
5-100-V120 0
5-2.5-2 0
V2 2.5V
therefore
V00 = V200 = V120 = 2.5V
30n
L 2.50.12A
200 -
200
202 20
2.5
-0.08A
30
300
300
302
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10Ω +2.5V 5V + 120 5-100-V120 0 5-2.5-2 0 V2 2.5V therefore V00 = V200 = V120 = 2.5V 30n L 2.50.12A 200 - 200 202 20 2.5 -0.08A 30 300 300 302

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