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7In(x) dx

7In(x) dx

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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7In(x) dx The integral is not improper. Since the integral has an infinite interval of integration, the integral is improper. Since y=In(x) has a vertical asymptote at x=1, the integral is improper. Since y=In(x) has a vertical asymptote at x=0, the integral is improper. sec(x) dx Since y=sec(x) has a vertical asymptote at x=-4, the integral is improper. Since the integral has an infinite interval of integration, the integral is improper. The integral is not improper. Since y=sec(x) has a vertical asymptote at x=0, the integral is improper. 1 1 dx (x-6)4 1 has a vertical asymptote at x=0, the integral is improper. Since y=- (x-6)4 The integral is not improper. 1 has a vertical asymptote at x=6, the integral is improper. (x-6)4 Since y= Since the integral has an infinite interval of integration, the integral is improper.
Transcribed Image Text:7In(x) dx The integral is not improper. Since the integral has an infinite interval of integration, the integral is improper. Since y=In(x) has a vertical asymptote at x=1, the integral is improper. Since y=In(x) has a vertical asymptote at x=0, the integral is improper. sec(x) dx Since y=sec(x) has a vertical asymptote at x=-4, the integral is improper. Since the integral has an infinite interval of integration, the integral is improper. The integral is not improper. Since y=sec(x) has a vertical asymptote at x=0, the integral is improper. 1 1 dx (x-6)4 1 has a vertical asymptote at x=0, the integral is improper. Since y=- (x-6)4 The integral is not improper. 1 has a vertical asymptote at x=6, the integral is improper. (x-6)4 Since y= Since the integral has an infinite interval of integration, the integral is improper.
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