8( 1 f(x)= 7( 2 ; х%3D1, 2, 3 probability distribution (a)P(X < 1) = (b)P(X > 1) = (с) Р(2 1) = [equation] %3D
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- If x² + 2y + 3z7 = x2 + 2y² + 3z2 = x3 + 2y3 + 3z3 = 2, and x₂x3 + 2y2y3 + 3z2Z3 = X3X1 + 2y3v1 +3Z3Z1 = x1x₂ + 2y1y₂ + 3z₁²₂ = 1, X1 then find the value of x₂ X3 Y₁ Y2 Y3 Z1 Z2 Z3X.19 Identify equivalent linear expressions II YP^(8) Select the expressions that are equivalent to 7(q+5)3. -4 2xdx J2 x²-4x+8
- About how much does x²/(1 + y) change if (x, y) changes from (10,4) to (10.1,3.9)?Given f(x)=x + 2 and g (x)= 4-x^2 , find the following 1) (f*g)(x) 2) (g*f)(x) 3) (g*f)(-2) Given f(x)=2x+5 and g(x) = 4x^2 +1 , find the following 4) (f*g)(x) 5) (g*f)(x) 6) (f*g)(-1/2)If y = (5x + 1)(2x¬1 – In 7), then y' will be A. (5x + 1) (+;) + 5(2x¬1 – In 7) B. (5x + 1) (-) 2. + 5(2x-1 – In 7) c - ÷) + 5(2x-+ – In 7) (5x + 1) (-2x² + 1) (-) 2 + 5(2x¬1 – In 7) D. (5x X'
- [(18 – 2) – (22)] dr -3FIND ALL VALUES OF POSITIVE INTEGERS OF y IF THE EQUATION IS: y= 3^-^(2x2+...+X^)+3^-{(n-1)(2X₂+...+Xn-1). +...+ 3^-2(2x2)+3^-1 2x₁+...+xn--34 WHERE X19X₂3... Xngh ARE ALSO POSITIVE INTEGERS. 29(a) Write the linear interpolation/ shape functions relevant for the 2D rectangular element shown below identifying the shape function for each node. Use the property that N,(x,)= 5, to derive the functions. For example, at node 1, N = 1, so using the equations of line 23 and line 34, we (x-a)(y-b) may write N = Sımilarly, interpolation function N2 should involve equations of %3D 4ab lines 34 and 14, and so on