help please q4 Evaluate the following expressions.19c. E k2k =1d. Σ (2+n?)a . Σ kb. 2 (2k + 1)k= 1k = 1n= 145m +535Σf. Σ 3-8)j= 1g. 2 k(4k + 7)h. 2 sinе.72m = 1k = 1n =019a. 2 k=(Type an integer or a simplified fraction.)k = 16b. 2 (2k + 1) = (Type an integer or a simplified fraction.)k= 1c. E k2(Type an integer or a simplified fraction.)k= 18d. E (2+ n2) = (Type an integer or a simplified fraction.)n = 15m +5e. 2(Type an integer or a simplified fraction.)е.7m = 13f. 2 (3j - 8) = U (Type an integer or a simplified fraction.)j= 19g. 2 k(4k + 7) = |(Type an integer or a simplified fraction.)k = 15h. Σ sin2(Type an integer or a simplified fraction.)n= 0

Name: help please q4 Evaluate the following expressions.19c. E k2k =1d. Σ (2
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Description: help please q4 Evaluate the following expressions.19c. E k2k =1d. Σ (2+n?)a . Σ kb. 2 (2k + 1)k= 1k = 1n= 145m +535Σf. Σ 3-8)j= 1g. 2 k(4k + 7)h. 2 sinе.72m = 1k = 1n =019a. 2 k=(Type an integer or a simplified fraction.)k = 16b. 2 (2k + 1) = (Type a

∑n = 18(2 + n2)= 3 +6 +11 +18+ 27 +38 +51 +66= 220

Answered: 8 d. Σ (2+n?) n=1

Math

Calculus

8 d. Σ (2+n?) n=1

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter7: Analytic Trigonometry

Section7.3: The Addition And Subtraction Formulas

Problem 72E

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Question

help please q4

Evaluate the following expressions.
19
c. E k2
k =1
d. Σ (2+n?)
a . Σ k
b. 2 (2k + 1)
k= 1
k = 1
n= 1
4
5m +5
3
5
Σ
f. Σ 3-8)
j= 1
g. 2 k(4k + 7)
h. 2 sin
е.
7
2
m = 1
k = 1
n =0
19
a. 2 k=
(Type an integer or a simplified fraction.)
k = 1
6
b. 2 (2k + 1) = (Type an integer or a simplified fraction.)
k= 1
c. E k2
(Type an integer or a simplified fraction.)
k= 1
8
d. E (2+ n2) = (Type an integer or a simplified fraction.)
n = 1
5m +5
e. 2
(Type an integer or a simplified fraction.)
е.
7
m = 1
3
f. 2 (3j - 8) = U (Type an integer or a simplified fraction.)
j= 1
9
g. 2 k(4k + 7) = |
(Type an integer or a simplified fraction.)
k = 1
5
h. Σ sin
2
(Type an integer or a simplified fraction.)
n= 0

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