8. A piano tuner simultaneously strikes a 262 Hz tuning fork and the middle C key on a piano and hears beats with a beat period of 0.500 s. What are
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8)
Given:
Frequency of the tuning fork is f1 =262 Hz
Period of beat is T=0.500 sec
So frequency of beat is given by,
fB=2 Hz
Using beat frequency formula,
fB=f1-f2
2=262-f2
f2=262-2
f2=260 Hz
Thus the possible frequency of the piano key is 260 Hz.
9)
Given: Length of pipe is L=0.8m
For pipe closed at one end,
λ=0.6m
So distance between node and adjacent anti-nodes is given by,
x=0.15m or x=0.2 m
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