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8. Determine the sum of the moments of the three loads about A. SAN 9. Determine the moment of force F3 about point A on the beam. |F-400 Ib -250 lb 250 F- s00 Ib 150 30 200 10. Find the x and y components of the resultant force and the resultant couple moment at point O. "s00 N 300 N 200 N - m 11. Determine the x and y components of the equivalent resultant force and specify the distance where this force acts. 500 N 400 N 12. Replace the loading system acting on the beam by an equivalent resultant force and couple moment at point O. 450N 02 m 200N m 15m 2m 15m 200N

8. Determine the sum of the moments of the three loads about A. SAN 9. Determine the moment of force F3 about point A on the beam. |F-400 Ib -250 lb 250 F- s00 Ib 150 30 200 10. Find the x and y components of the resultant force and the resultant couple moment at point O. "s00 N 300 N 200 N - m 11. Determine the x and y components of the equivalent resultant force and specify the distance where this force acts. 500 N 400 N 12. Replace the loading system acting on the beam by an equivalent resultant force and couple moment at point O. 450N 02 m 200N m 15m 2m 15m 200N

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ENGR 2301 13. Three horizontal forces are applied as shown to a vertical cast iron arm. Determine the resultant of the forces and the distance from the ground to its line of action when P=200 N. 150 mm 600 N 150 mm 400 N 150 mm 14. Determine the location (measured from A) of the equivalent resultant of the distributed load. 100 Ib/ft 50 lb/ft 6 ft ft Answer: 1-7: DDBDD, BB 8: 1 kN-m 9: M3 = 3000 ft · Ib 10: (FR)x = 400 N(+→), (Fr)y = -600 N (+1), (MR)o = -2000 N · m 11: F, = -300N (+→), F, = -800N (+1), d = 3m 12: FR = 294 N,0 = 40.1°&, (MR)o = 39.6 N · m clockwise 13: R = 800 N +, y = 0.1875 m = 187.5 mm 14: 9.33 ft
Transcribed Image Text:ENGR 2301 13. Three horizontal forces are applied as shown to a vertical cast iron arm. Determine the resultant of the forces and the distance from the ground to its line of action when P=200 N. 150 mm 600 N 150 mm 400 N 150 mm 14. Determine the location (measured from A) of the equivalent resultant of the distributed load. 100 Ib/ft 50 lb/ft 6 ft ft Answer: 1-7: DDBDD, BB 8: 1 kN-m 9: M3 = 3000 ft · Ib 10: (FR)x = 400 N(+→), (Fr)y = -600 N (+1), (MR)o = -2000 N · m 11: F, = -300N (+→), F, = -800N (+1), d = 3m 12: FR = 294 N,0 = 40.1°&, (MR)o = 39.6 N · m clockwise 13: R = 800 N +, y = 0.1875 m = 187.5 mm 14: 9.33 ft
ENGR 2301 Free-Response Questions 8. Determine the sum of the moments of the three loads about A. los m 1.5m- 05 m 05 m SAN 6KN SAN 3m 9. Determine the moment of force F3 about point A on the beam. |F- 400 Ib F2- 250 Ib F3= 500 Ib 150 250 30 200 al -4 f4 fA-4 A- 10. Find the x and y components of the resultant force and the resultant couple moment at point O. 500 N 300 N to | 200 N - m - 2 m 2 m 11. Determine the x and y components of the equivalent resultant force and specify the distance where this force acts. 500 N 400 N -2 m - 2 m 12. Replace the loading system acting on the beam by an equivalent resultant force and couple moment at point O. 450 N 30 0.2 m 200 N m 1.5 m- 2 m 1.5 m - 200 N 3
Transcribed Image Text:ENGR 2301 Free-Response Questions 8. Determine the sum of the moments of the three loads about A. los m 1.5m- 05 m 05 m SAN 6KN SAN 3m 9. Determine the moment of force F3 about point A on the beam. |F- 400 Ib F2- 250 Ib F3= 500 Ib 150 250 30 200 al -4 f4 fA-4 A- 10. Find the x and y components of the resultant force and the resultant couple moment at point O. 500 N 300 N to | 200 N - m - 2 m 2 m 11. Determine the x and y components of the equivalent resultant force and specify the distance where this force acts. 500 N 400 N -2 m - 2 m 12. Replace the loading system acting on the beam by an equivalent resultant force and couple moment at point O. 450 N 30 0.2 m 200 N m 1.5 m- 2 m 1.5 m - 200 N 3
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