8. sin 2a = Zsn AcosA 24 25 12 25 9. cos 2a =

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.2: Trigonometric Equations
Problem 105E
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Did I do 8 and 9 correctly?

3.
sina =
3n
<as 2n cos B =
<α< 2π
8.
3n
5
2.
Given:
17
Sinla-Cosa
くっる/% - Cos'a = 1
1. cosa = Sn'a-
2. sin ß = Sin B-CosB=|
225
1-4%39=289
%3D
%3D
%3D
15
17
2.
HCosa
-8?14
%3D
25
Sin q
23こCosa - 1
682
Sin B
CusB
17
3. tan a = Sina
Tosa
-3.5.15
4.
tan B =
%3D
-3/5
-/5
5. sin(a+B)= Sin ACosB+ SinBCesA
1.
品十%
15
17
20
片。-号
4
17
15
%3D
17
- 4,7
5.
ノフ
17
Transcribed Image Text:3. sina = 3n <as 2n cos B = <α< 2π 8. 3n 5 2. Given: 17 Sinla-Cosa くっる/% - Cos'a = 1 1. cosa = Sn'a- 2. sin ß = Sin B-CosB=| 225 1-4%39=289 %3D %3D %3D 15 17 2. HCosa -8?14 %3D 25 Sin q 23こCosa - 1 682 Sin B CusB 17 3. tan a = Sina Tosa -3.5.15 4. tan B = %3D -3/5 -/5 5. sin(a+B)= Sin ACosB+ SinBCesA 1. 品十% 15 17 20 片。-号 4 17 15 %3D 17 - 4,7 5. ノフ 17
8. sin 2a = 2sn AcosA
%3D
12
25
24
25
%3D
cos 2a = /-23in?A
1-2(%)
2.
18.
25
18
23
23
10. sin 3a = 35inA Cos A
Hint: Why did I ask #8 and #9?
Transcribed Image Text:8. sin 2a = 2sn AcosA %3D 12 25 24 25 %3D cos 2a = /-23in?A 1-2(%) 2. 18. 25 18 23 23 10. sin 3a = 35inA Cos A Hint: Why did I ask #8 and #9?
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Swokowski
Publisher:
Cengage