7, 8, 2, and 10 Find an equation of the tangent to the curve at the point corresponding to the given valueof the parameter.==√t, y=t²-2t; t = 48. =

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Answered: 8. = √t, y=t² - 2t; t = 4

Math

Calculus

8. = √t, y=t² - 2t; t = 4

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter6: Applications Of The Derivative

Section6.3: Implicit Differentiation

Problem 24E

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Question

7, 8, 2, and 10 Find an equation of the tangent to the curve at the point corresponding to the given value
of the parameter.
==√t, y=t²-2t; t = 4
8. =

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