80. A plate-type fuel element, having a thermal conductivity of 2 W/m-K, pro- duces heat. The heat source is uniformly distributed, having a source strength of 2.4E8 W/m³. One side of the fuel is insulated (due to symmetry), one side is maintained at 200 F, and remaining sides are exposed a convection boundary of 300 C and 34 kW/m²-K. Find the two-dimensional temperature distribution in the fuel at steady state condition. Questions and Problems 517 Insulated Boundary Insulated boundary cm т. - 20 с T,= 20 C r4" =1.0E8 W/m³- %3D т.- 200 с – 1500 W/m K -т,- 20 с 1 cm Tmm T - = 200 C Figure for Problem 79 Figure for Problem 80 T,- 300 C h- 34 kW/m².K T,- 300 C h = 34 kW/m².K

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Chapter2: Steady Heat Conduction
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80. A plate-type fuel element, having a thermal conductivity of 2 W/m-K, pro-
duces heat. The heat source is uniformly distributed, having a source strength of
2.4E8 W/m?. One side of the fuel is insulated (due to symmetry), one side is
maintained at 200 F, and remaining sides are exposed a convection boundary of
300 C and 34 kW/m².K. Find the two-dimensional temperature distribution in the
fuel at steady state condition.
Questions and Problems
517
Insulated Boundary
Insulated boundary
Il mm
1 ст
Т, - 20 С
|т, - 20 С
tġ" =1.0E8 W/m³-
т- 200 С
h = 1500 W/m K
T,-
1 cm
- 20 C
T= 200 C
mm
Figure for Problem 79
Figure for Problem 80
T,= 300 C
h= 34 kW/m?.K
ɔ 008 ='1 -
h = 34 kW/m².K
Transcribed Image Text:80. A plate-type fuel element, having a thermal conductivity of 2 W/m-K, pro- duces heat. The heat source is uniformly distributed, having a source strength of 2.4E8 W/m?. One side of the fuel is insulated (due to symmetry), one side is maintained at 200 F, and remaining sides are exposed a convection boundary of 300 C and 34 kW/m².K. Find the two-dimensional temperature distribution in the fuel at steady state condition. Questions and Problems 517 Insulated Boundary Insulated boundary Il mm 1 ст Т, - 20 С |т, - 20 С tġ" =1.0E8 W/m³- т- 200 С h = 1500 W/m K T,- 1 cm - 20 C T= 200 C mm Figure for Problem 79 Figure for Problem 80 T,= 300 C h= 34 kW/m?.K ɔ 008 ='1 - h = 34 kW/m².K
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