8:3m V.A ヒo2m-メ Determine Cantroid Y dmax if M= 5 K N.n
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- MN = 48 SN = 79 (1&3) with thickness of 7.5mmA solid steel shaft is stressed at 100 Mpa when twisted through 6 degrees. Compute the Diameter of the shaft and the Power it transmits at 25 Hz given the following data: Length of shaft = 15 metersG = 83 GPasolve/ show solution for given answer equations kb = (Ab*Eb)/ g and kc = (Ac*Ec) / g g- estimated effective length
- A solid steel shaft, whose Sy= 300 MPa and Su= 400 MPa, is used to transmit 3000 kW at 800 rpm. Determine its diameter.(6) A solid shaft is used to transmit 75kW @ 550rpm. If the shaft design stress will not exceed 26N/mm2 , determine the diameter of the solid shaft.(5) A gas engine valve spring is loaded to 35kgf when the valve is closed & 52kgf hen the valve is open. The valve lift is 8mm. The outside diameter is to be from 38mm~45mm, & the permissible stress is 413N/mm2 . Determine: (a) the wire & outside diameter; (b) the number of effective coils; (c) the free length when it is squared & ground.
- A solid shaft is transmitting 1MW at 240rpm . Determine the diameter of the shaft if the maximum torque transmitted exceeds the mean torque by 20%.Take the maximum allowable shear stress are 60MPa.Please solve clearly step by step otherwise don't attempt.will report. A shaft is required to transmit 285 kW power at 255 r.p.m. The maximum torque may be 1.8 times the mean torque. The shear stress in the shaft should not exceed 46 MPa and the twist 1.2° per metre length. Determine the diameter required if, (i) The shaft is solidPlease don't copy Find the torque and power transmitted by a 100 mm diameter shaft, if maximum angle of twist and length of shaft are 1.2° and 2 m. Take G = 70 GPa, speed of shaft = 230 r.p.m.
- Use G = 11.6 x 103 ksi for the circular shafts. Determine the maximum power (k-in/s) transmitted by the shaft at 180 rev/min. (Numerical absolute answer only without units in 3 decimal places)Repeat Problem 11.2-3 assuming that R= 10 kN · m/rad and L = 2 m.A = 5 in^2 E = 29,000 ksi I = 5 in^4 Setup [k] and Solve for the displacements.