E Ahmad Awadalla xTrad. & Market E XO Algebra 1: Sectic XO EXAM 8-5 to 8-7 xnon-assessment-delivery/start/4735051126?action=onresume&submissionld 4343009879 Writing Assignn x9 English 1: Sectio xO 948) Graph a Cx9 9-1 PracticeISDCOURSESGROUPSRESOURCESGRADE REPORT509-1 Practice Day 14 ofA population of amoebas in a petri dish will triple in size every 20 minutes. At the start of an experiment, the population is 800. The functiony = 800(3) where x is the number of 20 minute periods, models the population growth. How many amoebas are in the petri dish after 3 hours?In 3 hours there areamoebas.: 1,574,640: 15,746,400: 21,600: 800: 2,789,427,520,8002346.NextSupport | Schoology Blog I PRIVACY POLICY I Terms of UseSchoologsh9 GNOCchCREATIVE4. ad Awadall xO Trad. & Market E X9 Algebra 1: Sectic X9 EXAM 8-5 to 8- xO Writing Assignn xnent-delivery/start/4735051126?action%3Donresume&submissionld=434300987e English 1: Sectio x(948) GraphaCOURSESGROUPSRESOURCESGRADE REPORT-1 Practice Day 1A population of amoebas in a petri dish will triple in size every 20 minutes. At the start of an experiment, the population is 800. The functionu = 800(3)7, where x is the number of 20 minute periods, models the population growth. How many amoebas are in the petri dish after 3 hours?In 3 hours there areamoebas.: 15,746,400: 21,600: 800:: 2,789,427,520,800: 1,574,64014Terms of UseSupport | Schoology Blog | PRIVACY POLICYAOC

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Ans; in a 3 hr time there are 3*60=180 minutes . Now x is the number of 20 minute period so in 20…

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9-1 Practice Day 1 A population of amoebas in a petri dish will triple in size every 20 minutes. At the start of an experiment, the population is 800. The function 800(3)", where x is the number of 20 minute periods, models the population growth. How many amoebas are in the petri dish after 3 hours? In 3 hours there are amoebas

9-1 Practice Day 1 A population of amoebas in a petri dish will triple in size every 20 minutes. At the start of an experiment, the population is 800. The function 800(3)", where x is the number of 20 minute periods, models the population growth. How many amoebas are in the petri dish after 3 hours? In 3 hours there are amoebas

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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In his doctoral thesis, L. A. Beckel (University of Minnesota, 1982) studied the social behavior of river otters during the mating season. An important role in the bonding process of river otters is very short periods of social grooming. After extensive observations, Dr. Beckel found that one group of river otters under study had a frequency of initiating grooming of approximately 1.7 for each 10 minutes. Suppose that you are observing river otters for 30 minutes. Let r = 0, 1, 2, ... be a random variable that represents the number of times (in a 30-minute interval) one otter initiates social grooming of another. a) What is ?? b) Write out the formula for the probability distribution of the random variable r. P(r) = _________ c) Find the probability that one otter will initiate social grooming four or more times during the 30-minute observation period. (Round your answer to four decimal places.)
In his doctoral thesis, L. A. Beckel (University of Minnesota, 1982) studied the social behavior of river otters during the mating season. An important role in the bonding process of river otters is very short periods of social grooming. After extensive observations, Dr. Beckel found that one group of river otters under study had a frequency of initiating grooming of approximately 1.7 for each 10 minutes. Suppose that you are observing river otters for 30 minutes. Let r = 0, 1, 2, ... be a random variable that represents the number of times (in a 30-minute interval) one otter initiates social grooming of another. a) Find the probabilities that in your 30 minutes of observation, one otter will initiate social grooming four times, five times, and six times. (Round your answers to four decimal places.) P(4) = P(5) = P(6) = b) Find the probability that one otter will initiate social grooming less than four times during the 30-minute observation period. (Round your answer…
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In his doctoral thesis, L. A. Beckel (University of Minnesota, 1982) studied the social behavior of river otters during the mating season. An important role in the bonding process of river otters is very short periods of social grooming. After extensive observations, Dr. Beckel found that one group of river otters under study had a frequency of initiating grooming of approximately 1.7 for each 10 minutes. Suppose that you are observing river otters for 40 minutes. Let r = 0, 1, 2, ... be a random variable that represents the number of times (in a 40-minute interval) one otter initiates social grooming of another. Lambda = 6.8 (b) Find the probabilities that in your 40 minutes of observation, one otter will initiate social grooming four times, five times, and six times. (Round your answers to four decimal places.) P(4) = P(5) = P(6) =
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Suppose a company charges a premium of $150 per year for an insurance policy for storm damage to roofs. Actuarial studies show that in case of a storm, the insurance company will pay out an average of $8000 for damage to a composition shingle roof and an average of $12,000 for damage to a shake roof. They also determine that out of every 10,000 policies, there are 7 claims per year made on composition shingle roofs and 11 claims per year made on shake roofs. What is the company’s expected value (i.e., expected profit) per year of a storm insurance policy? What annual profit can the company expect if it issues 1000 such policies? Determine the probability of a composition shingle roof claim out of 10,000 = ______ Determine the probability of a shake roof claim out of 10,000 = ______ How many claims are made out of 10,000? = _______ What is the probability of no claims out of 10,000? = _______ How much does each shingle roof claim cost the company, don’t forget each person pays $150…
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