9 In order to evaluate the following integral 1 -√2/cos-¹(√x) dx 1 =- we first use the substitution W we use Integration by Parts to obtain I= W cos¹W + the above I = W cos-¹ W s = √x, then W √1-W² S dW W √1-W² dW

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Conic Sections
Section8.2: More Parabolas And Some Circles
Problem 63.2PS: By expanding (xh)2+(yk)2=r2, we obtain x22hx+h22ky+k2r2=0. When we compare this result to the form...
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In order to evaluate the following integral
1
1= -√2+x²
-1
cos-¹(√x) dx
we first use the substitution W = √x, then
we use Integration by Parts to obtain
I = W cos¹W+
O the above
1₁
√1-W²
I = W cos ¹ W
W
√1-W²
fx
dW
Transcribed Image Text:2 ! 6:38 %E0 In order to evaluate the following integral 1 1= -√2+x² -1 cos-¹(√x) dx we first use the substitution W = √x, then we use Integration by Parts to obtain I = W cos¹W+ O the above 1₁ √1-W² I = W cos ¹ W W √1-W² fx dW
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