9) y = (02 + 50) tanh~1 (0 + 4) A) (20 + 5) tanh~1 (0 + 4) - C)-8+3 02 +50 1+ (0+4)²2 e B) (20 + 5) tanh~1 (0 + 4) - 043 D) (20+5)- 1 0+15

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Need 9-15
Find the derivative of y with respect to the appropriate variable.
8) y = sinh-1 V9x
A)
2√√9x(1 +9x)
C)
9) y = (02 + 50) tanh~1 (0 +4)
A) (20 + 5) tanh-1 (0 + 4) -
C)
0+3
10) y = 9 tanh-1 (cos x)
1
A) In
sin x
-9 sin x
1+ cos²x
B)
coth x =
2√√9x(1 +9x)
02 +50
1+ (0+4)2
14) f(x) = 3x2 + 4x + 1, a = 3
A) L(x)=22x - 26
15) f(x)=√√4x + 49, a = 0
Find the linearization L(x) of f(x) at x = a.
A) L(x) = x - 7
C)
B) L(x)=22x + 28
11) Verify the identity using the definitions of hyperbolic functions.
e2x + 1
e2x-1
B) L(x) = x + 7
B) (20 + 5) tanh~1 (0+4)
2
√1+9x
D) (20+5)-
B)
D)
-9
sin x
12) Use the fundamental identity cosh2 x - sinh2 x = 1 to verify the identity.
1 - tanh2 x = sech2 x
-9
COS X
13) Derive the formula given that d/dx (cosh x) = sinh x and d/dx (sinh x) =
cosh x.
d/dx (coth x) = -csch² x
0+15
D)
C) L(x) = 14x - 26
2√√9x(9x-1)
C) L(x) = 2x - 7
0
0+3
11)
12)
13)
D) L(x)= 14x + 28
D) L(x)=x+7
8)
9)
10)
14)
15)
Transcribed Image Text:Find the derivative of y with respect to the appropriate variable. 8) y = sinh-1 V9x A) 2√√9x(1 +9x) C) 9) y = (02 + 50) tanh~1 (0 +4) A) (20 + 5) tanh-1 (0 + 4) - C) 0+3 10) y = 9 tanh-1 (cos x) 1 A) In sin x -9 sin x 1+ cos²x B) coth x = 2√√9x(1 +9x) 02 +50 1+ (0+4)2 14) f(x) = 3x2 + 4x + 1, a = 3 A) L(x)=22x - 26 15) f(x)=√√4x + 49, a = 0 Find the linearization L(x) of f(x) at x = a. A) L(x) = x - 7 C) B) L(x)=22x + 28 11) Verify the identity using the definitions of hyperbolic functions. e2x + 1 e2x-1 B) L(x) = x + 7 B) (20 + 5) tanh~1 (0+4) 2 √1+9x D) (20+5)- B) D) -9 sin x 12) Use the fundamental identity cosh2 x - sinh2 x = 1 to verify the identity. 1 - tanh2 x = sech2 x -9 COS X 13) Derive the formula given that d/dx (cosh x) = sinh x and d/dx (sinh x) = cosh x. d/dx (coth x) = -csch² x 0+15 D) C) L(x) = 14x - 26 2√√9x(9x-1) C) L(x) = 2x - 7 0 0+3 11) 12) 13) D) L(x)= 14x + 28 D) L(x)=x+7 8) 9) 10) 14) 15)
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