9. Find a parametric equation for the line that is orthogonal to the surface 2 at the point (1, 1, 2). Xyz

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
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Chapter11: Topics From Analytic Geometry
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9. Find a parametric equation for the line that is orthogonal to the surface
xyz = 2 at the point (1, 1, 2).
Solution.
The normal vector to the surface f(x, y, z) = 2 with f (x, y, z) = xyz is
Vf(7, y, 2) yzi + α2j + xyk.
Thus, the normal vector at (x, y, z) = (1, 1,2) is
i = Vf(1,1, 2) = 2i + 2j + k.
The normal vector n
(2, 2, 1) is a direction vector of the line, so a
parametric equation of the line is
(x, y, z) = (1, 1, 2) + t(2,2, 1),
or
x = 1+ 2t,
y = 1+ 2t,
z = 2+t.
Transcribed Image Text:9. Find a parametric equation for the line that is orthogonal to the surface xyz = 2 at the point (1, 1, 2). Solution. The normal vector to the surface f(x, y, z) = 2 with f (x, y, z) = xyz is Vf(7, y, 2) yzi + α2j + xyk. Thus, the normal vector at (x, y, z) = (1, 1,2) is i = Vf(1,1, 2) = 2i + 2j + k. The normal vector n (2, 2, 1) is a direction vector of the line, so a parametric equation of the line is (x, y, z) = (1, 1, 2) + t(2,2, 1), or x = 1+ 2t, y = 1+ 2t, z = 2+t.
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