9. the series diverges by the 2. Thus the series converges when r + 3| < 1, or - < a < -. At z = - Divergence Test. At r = - 3 the series diverges by the Divergence Test.. Thus the interval of convergence 2'
9. the series diverges by the 2. Thus the series converges when r + 3| < 1, or - < a < -. At z = - Divergence Test. At r = - 3 the series diverges by the Divergence Test.. Thus the interval of convergence 2'
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.2: Exponents And Radicals
Problem 28E
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Question
For number 34 for the part circled in pink , can you show the Algebra for how we solved the inequality to get -9/2 and -3/2?
Transcribed Image Text:x = 0, the series diverges as well by the Divergence Test. Thus the interval of convergence is (0, 2).
11.2.34 Using the Ratio Test:
(-2)사1(z + 3)서1
3k+2
3k+1
|ak+1l
|ak|
lim
k00
(-2)*(x+ 3)k
+3|.
-을 <u< -흙. At z= -
9.
the series diverges by the
2'
Thus the series converges when x + 3| < 1, or
< x <
3.
Divergence Test. At r = -
the series diverges by the Divergence Test. Thus the interval of convergence
21
(을
9.
is
Transcribed Image Text:(-2)* (x +3)*
34.
3k+1
k=0
,20 xk
00
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