-9x2-28x+12 y' = (5x2-3x+2) 3x2+4 4) Differentiate y = 5x2—3х+2 2 4x3-2 y's x2—5х+1 2(2x4-20x3+6x2+2x-E 5) Differentiate y = (x²–5x+1)²

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Show the expanded solution on number 4 and number 5

.2
5x2+8х-15
y' =
x+3
3) Differentiate y =
5х+4
(5x+4)2
-9x2-28x+12
y' =
(5x²–3x+2)?
3x2+4
4) Differentiate y% =
5x2-Зх+2
4x3-2
2(2x4-20x3+6x2+2x-5)
5) Differentiate y =
%3D
х2—5х+1
(x²–5x+1)
Transcribed Image Text:.2 5x2+8х-15 y' = x+3 3) Differentiate y = 5х+4 (5x+4)2 -9x2-28x+12 y' = (5x²–3x+2)? 3x2+4 4) Differentiate y% = 5x2-Зх+2 4x3-2 2(2x4-20x3+6x2+2x-5) 5) Differentiate y = %3D х2—5х+1 (x²–5x+1)
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