_6. What is the derivative of f(x) = (5 – x²)²? а. 2(5- х2) b. 10 – 2x2 C. 4x3 – 20x d.(5 - x?)(5 - х?) 7. What is the equation of the tangent line and the normal line to y = x² – 4x + 2 at (4,2) respectively? a. y = -4x +14 and y = ÷x - 3 b. y = 4x – 14 and y = -x+ 3 C. y = 4x – 14 and y = ÷x +3 d. y = -4x + 14 and y = -x - 3 _8. If y = (2x + 7)², then what is 27 dy, dx dy а. = 2(2x + 7) dy C. = 2 %3D dx dy b. dx dy d. = 4x = 8x + 28 _9. If y = (2x2 – 1), then what is y'? | а. у' — 2x(2х? - 1) + b. y' = 4x(2x² – 1) с. у'%3D 2x(2х? —1)? d. y' = 2x(2x² – 1)2 | 10. If y = v3x – 7, then what is 2? dx dy a. dy 2 %3D С. %3D 2/3x-7 3/3x-7 3x dy b. dx dy d. dx %3D 3/3x-2 V2x-7 11. If y = V6x+1, then what is 9? dx dy = 2(6x + 1) dy С. c. = 2(6x – 1)5 a. %3D | dx dx dy (x² + 6x) dy b. = d. = 3(6x +1)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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6. What is the derivative of f(x) = (5 – x²)²?
а. 2(5 — х2)
b. 10 – 2x2
C. 4x3 – 20x
d.(5 — x2)(5 — х?)
_7. What is the equation of the tangent line and the normal line to y = x? – 4x + 2 at (4,2)
respectively?
а. у%3D—4x + 14 аnd y %3D -x - 3
b. y = 4x – 14 and y = -x+3
С. у %3D 4х — 14 and y %3D—x +3
d. y = -4x + 14 and y = -x – 3
_8. If y = (2x +7)², then what is 9?
dx
dy
a.
= 2(2x + 7)
C.
dx
dy – 2
dx
dy
b.
dx
dy
= 4x
d.
= 8x + 28
dx
1
_9. If y = (2x2 – 1), then what is y'?
a. y' = 2x(2x² – 1)
b. y' = 4x(2x² – 1)
с. у' %3D 2x(2х2 - 1)?
d. y' = 2x(2x² – 1)
_10. If y = 3x – 7, then what is 4?
dx
dy
2/3x-7
dy
C.
dx
3
2
а.
3/3x-7
3x
dx
dy
b.
dx
dy
d.
dx
7
%3D
3/3x-2
V2x-7
_11. If y = V6x + 1, then what is ?
dx
dy = 2(6x + 1)
(x² + 6x)
dy = 2(6x – 1)5
a.
С.
dx
%3D
dy
b.
dx
= ³
dy
d.
dx
= 3(6x + 1)
I| ||
Transcribed Image Text:6. What is the derivative of f(x) = (5 – x²)²? а. 2(5 — х2) b. 10 – 2x2 C. 4x3 – 20x d.(5 — x2)(5 — х?) _7. What is the equation of the tangent line and the normal line to y = x? – 4x + 2 at (4,2) respectively? а. у%3D—4x + 14 аnd y %3D -x - 3 b. y = 4x – 14 and y = -x+3 С. у %3D 4х — 14 and y %3D—x +3 d. y = -4x + 14 and y = -x – 3 _8. If y = (2x +7)², then what is 9? dx dy a. = 2(2x + 7) C. dx dy – 2 dx dy b. dx dy = 4x d. = 8x + 28 dx 1 _9. If y = (2x2 – 1), then what is y'? a. y' = 2x(2x² – 1) b. y' = 4x(2x² – 1) с. у' %3D 2x(2х2 - 1)? d. y' = 2x(2x² – 1) _10. If y = 3x – 7, then what is 4? dx dy 2/3x-7 dy C. dx 3 2 а. 3/3x-7 3x dx dy b. dx dy d. dx 7 %3D 3/3x-2 V2x-7 _11. If y = V6x + 1, then what is ? dx dy = 2(6x + 1) (x² + 6x) dy = 2(6x – 1)5 a. С. dx %3D dy b. dx = ³ dy d. dx = 3(6x + 1) I| ||
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