_6. What is the derivative of f(x) = (5 – x²)²? а. 2(5- х2) b. 10 – 2x2 C. 4x3 – 20x d.(5 - x?)(5 - х?) 7. What is the equation of the tangent line and the normal line to y = x² – 4x + 2 at (4,2) respectively? a. y = -4x +14 and y = ÷x - 3 b. y = 4x – 14 and y = -x+ 3 C. y = 4x – 14 and y = ÷x +3 d. y = -4x + 14 and y = -x - 3 _8. If y = (2x + 7)², then what is 27 dy, dx dy а. = 2(2x + 7) dy C. = 2 %3D dx dy b. dx dy d. = 4x = 8x + 28 _9. If y = (2x2 – 1), then what is y'? | а. у' — 2x(2х? - 1) + b. y' = 4x(2x² – 1) с. у'%3D 2x(2х? —1)? d. y' = 2x(2x² – 1)2 | 10. If y = v3x – 7, then what is 2? dx dy a. dy 2 %3D С. %3D 2/3x-7 3/3x-7 3x dy b. dx dy d. dx %3D 3/3x-2 V2x-7 11. If y = V6x+1, then what is 9? dx dy = 2(6x + 1) dy С. c. = 2(6x – 1)5 a. %3D | dx dx dy (x² + 6x) dy b. = d. = 3(6x +1)
_6. What is the derivative of f(x) = (5 – x²)²? а. 2(5- х2) b. 10 – 2x2 C. 4x3 – 20x d.(5 - x?)(5 - х?) 7. What is the equation of the tangent line and the normal line to y = x² – 4x + 2 at (4,2) respectively? a. y = -4x +14 and y = ÷x - 3 b. y = 4x – 14 and y = -x+ 3 C. y = 4x – 14 and y = ÷x +3 d. y = -4x + 14 and y = -x - 3 _8. If y = (2x + 7)², then what is 27 dy, dx dy а. = 2(2x + 7) dy C. = 2 %3D dx dy b. dx dy d. = 4x = 8x + 28 _9. If y = (2x2 – 1), then what is y'? | а. у' — 2x(2х? - 1) + b. y' = 4x(2x² – 1) с. у'%3D 2x(2х? —1)? d. y' = 2x(2x² – 1)2 | 10. If y = v3x – 7, then what is 2? dx dy a. dy 2 %3D С. %3D 2/3x-7 3/3x-7 3x dy b. dx dy d. dx %3D 3/3x-2 V2x-7 11. If y = V6x+1, then what is 9? dx dy = 2(6x + 1) dy С. c. = 2(6x – 1)5 a. %3D | dx dx dy (x² + 6x) dy b. = d. = 3(6x +1)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
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