Get the SOP and POS representation of the truth table below in both canonical and standard form. Moreover, construct its logical circuit diagram. A 0 ܘ ܘ ܘ 1 1 Input B 0 0 1 1 0 0 CO-O с 0 0 1 0 1 Output F 0 0 1 0 1 1

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Get the SOP and POS representation of the truth table below in both canonical
and standard form. Moreover, construct its logical circuit diagram.
A
ܘ ܘ ܘ ܘ ܝ
1
1
1
1
Input
B
0
0
1
1
0
0
1
1
с
0
1
0
1
0
1
0
1
Output
F
0
0
1
0
1
1
1
1
Transcribed Image Text:Get the SOP and POS representation of the truth table below in both canonical and standard form. Moreover, construct its logical circuit diagram. A ܘ ܘ ܘ ܘ ܝ 1 1 1 1 Input B 0 0 1 1 0 0 1 1 с 0 1 0 1 0 1 0 1 Output F 0 0 1 0 1 1 1 1
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Follow-up Question

follow this format. and make sure to draw the logical circuit diagram in connected manner.

Using a truth table, we can determine the SOP and POS representation.
Input
Output
Maxterms
F
0
1
0
1
A
0
0
1
1
F = m + m²
F = A'B + AB
B
0
1
0
1
F = (A' + A)B
F = B
Term
A'B'
A'B
AB'
AB
SOP
For SOP, we get the combinations where output is 1.
Minterms
(canonical)
(standard)
Designation
mo
m₁
m₂
m3
Term
A+B
A+B'
A'+B
A'+B'
Designation
Mo
M₁
M₂
M3
POS
For POS, we get the combinations where output is O.
F = MoM₂
F = (A+B)(A'+B)
(canonical)
Transcribed Image Text:Using a truth table, we can determine the SOP and POS representation. Input Output Maxterms F 0 1 0 1 A 0 0 1 1 F = m + m² F = A'B + AB B 0 1 0 1 F = (A' + A)B F = B Term A'B' A'B AB' AB SOP For SOP, we get the combinations where output is 1. Minterms (canonical) (standard) Designation mo m₁ m₂ m3 Term A+B A+B' A'+B A'+B' Designation Mo M₁ M₂ M3 POS For POS, we get the combinations where output is O. F = MoM₂ F = (A+B)(A'+B) (canonical)
Solution
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Follow-up Question

Draw the logical circuit diagram, make sure that the overall logical circuits are connected.

Solution
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