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- Let ƒ(x) = (x2 - 9)/(x + 3). a. Make a table of the values of ƒ at the points x = -3.1, -3.01, -3.001, and so on as far as your calculator can go. Then estimate limx--> -3 ƒ(x). What estimate do you arrive at if you evaluate ƒ at x = -2.9, -2.99, -2.999,...... instead? b. Support your conclusions in part (a) by graphing ƒ near c = -3 and using Zoom and Trace to estimate y-values on the graph as x -->-3.Find the limit: limx→0 x3sin(1/3x3)1. Is it possible that f(2) = 5 but limx→2f(x) = 7? If so, what kind of function can satisfy this?
- what is lim of x approaches -8 from the left of 7x+56/abolute value of x+8If f(x)=x2−9x−3 , what is limx→3+x2−9x−3 , limx→3−x2−9x−3, and f(3) ? Is f(x) continuous at 3?Evaluate the Limits: a) limt->-1(t2+3t+2)/(t2-t-2) b) limx->9 (9x-x2)/(3-x1/2) c) limx->-inf (ex-e-x)/(ex+e-x) Do Not Use L'Hopital's Rule
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