A 1-kilogram mass is attached to a spring whose constant is 24 N/m, and the entire system is then submerged in a liquid that imparts a damping force numerically equal to 11 times the instantaneous velocity. Determine the initial conditions and equations of motion if the following is true. (a) the mass is initially released from rest from a point 1 meter below the equilibrium position x(0) = m x'(0) = m/s x(t) = (b) the mass is initially released from point 1 meter below the equilibrium position with an upward velocity of 11 m/s x(0) = x'(0) = x(t) = m m m/s m

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.1: Solutions Of Elementary And Separable Differential Equations
Problem 59E: According to the solution in Exercise 58 of the differential equation for Newtons law of cooling,...
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A 1-kilogram mass is attached to a spring whose constant is 24 N/m, and the entire system is then submerged in a liquid that imparts a damping force numerically equal to 11 times the instantaneous
velocity. Determine the initial conditions and equations of motion if the following is true.
(a) the mass is initially released from rest from a point 1 meter below the equilibrium position
m
x(0) =
x'(0) =
x(t) =
m/s
x(t) =
(b) the mass is initially released from a point 1 meter below the equilibrium position with an upward velocity of 11 m/s
x(0) =
x'(0) =
m
m
m/s
m
Transcribed Image Text:A 1-kilogram mass is attached to a spring whose constant is 24 N/m, and the entire system is then submerged in a liquid that imparts a damping force numerically equal to 11 times the instantaneous velocity. Determine the initial conditions and equations of motion if the following is true. (a) the mass is initially released from rest from a point 1 meter below the equilibrium position m x(0) = x'(0) = x(t) = m/s x(t) = (b) the mass is initially released from a point 1 meter below the equilibrium position with an upward velocity of 11 m/s x(0) = x'(0) = m m m/s m
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