A 1) min pxx + pyy s.t. Xxx + ayy =ū x, L(x, y, 2) = px x + P4y px + xxλ=0 Py + xy₁ = 0 2²: xxx+xxy_ū = 0 y since u(x, y) represents X: when y=0 x = U x=0 ут = u ху 2) elp, u) = min 3) W = = min { p²² x,y x(p₁w) = + X[Xxx + xyy _ Ñ] الله x (p₁w) = w PX y (p₁w) = w Py (1) (2) (3) min { Px, P4 & V(D,W) 7 xx ay (1)/(2) Poc : PY perfect subs, we have corner solutions: → h₂c (p₁ū) = ū xx ⇒hy (p₁ ū) = ū xy By Y ū Ky min & Px, х,у 4) Roy's identity : x (p, w) = -2% / av or o or o PLZ dy = xx W Px xx corner solution ----wa -wkx wax Px²¹ /xx) wxx WRX - Px = 10

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter5: Orthogonality
Section5.3: The Gram-schmidt Process And The Qr Factorization
Problem 11AEXP
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A
1) min pxx + pyy s.t. Xxx + ayy =ū
x,
L(x, y, 2) = px x + P4y
px + xxλ=0
Py + xy₁ = 0
2²: xxx+xxy_ū = 0
y
since u(x, y) represents
X:
when y=0 x = U
x=0
ут
= u
ху
2) elp, u) = min
3) W
=
= min { p²²
x,y
x(p₁w) =
+ X[Xxx + xyy _ Ñ]
الله
(1)
(2)
(3)
x (p₁w) = w
PX
y (p₁w) = w
Py
min { Px, P4 & V(D,W)
7
xx
ay
min & Px,
х,у
(1)/(2) Poc
:
PY
perfect subs, we have corner solutions:
→ h₂c (p₁ū) = ū
xx
⇒hy (p₁ ū) = ū
xy
By Y ū
Ky
PLZ
dy
-4) Roy's identity : X (p, W) = ax / av
x
or o
or o
= xx
W
Px
xx
corner solution
----wa
-wkx
wax Px
wax Px²¹
/xx)
Transcribed Image Text:A 1) min pxx + pyy s.t. Xxx + ayy =ū x, L(x, y, 2) = px x + P4y px + xxλ=0 Py + xy₁ = 0 2²: xxx+xxy_ū = 0 y since u(x, y) represents X: when y=0 x = U x=0 ут = u ху 2) elp, u) = min 3) W = = min { p²² x,y x(p₁w) = + X[Xxx + xyy _ Ñ] الله (1) (2) (3) x (p₁w) = w PX y (p₁w) = w Py min { Px, P4 & V(D,W) 7 xx ay min & Px, х,у (1)/(2) Poc : PY perfect subs, we have corner solutions: → h₂c (p₁ū) = ū xx ⇒hy (p₁ ū) = ū xy By Y ū Ky PLZ dy -4) Roy's identity : X (p, W) = ax / av x or o or o = xx W Px xx corner solution ----wa -wkx wax Px wax Px²¹ /xx)
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