A 1.10-kg particle moves in the xy plane with a velocity of v = (3.90 î - 3.70 j) m/s. Determine the angular momentum of the particle about the origin when its position vector is ř = (1.50 î + 2.20 j) m. î + Jê) kg • m²/s
A 1.10-kg particle moves in the xy plane with a velocity of v = (3.90 î - 3.70 j) m/s. Determine the angular momentum of the particle about the origin when its position vector is ř = (1.50 î + 2.20 j) m. î + Jê) kg • m²/s
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Transcribed Image Text:A 1.10-kg particle moves in the xy plane with a velocity of v = (3.90 î - 3.70 ĵ) m/s. Determine the angular momentum of the particle about the origin when its position vector is ř = (1.50 î + 2.20 ĵ) m.
k) kg · m²/s
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