A 14-ft-long simply supported beam has a uniformly distributedlive load of 3 kips/ft and a uniformly distributed dead loadof 2 kips/ft. It is laterally supported only at its ends. Determine theleast weight A992 steel W shape that will work.
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A 14-ft-long simply supported beam has a uniformly distributed
live load of 3 kips/ft and a uniformly distributed dead load
of 2 kips/ft. It is laterally supported only at its ends. Determine the
least weight A992 steel W shape that will work.
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- PLEASE HELP ME How to solve Cantilever Method! No need SOLUTIONS Using Cantilever Method, determine the following in kN (4 decimal places): ________1. Axial Force at Member AC & CA ________2. Axial Force at Member BD & DB ________3. Axial Force at Member CF & FC ________4. Axial Force at Member DG & GD ________5. Axial Force at Member EH & HE ________6. Axial Force at Member FI & IF ________7. Axial Force at Member GJ & JG ________8. Axial Force at Member HK & KH1. A cantilever R.C. beam is 280 mm x 500 mm deep and is reinforced with 4- 20 mm diam bars for tension. Using an effective depth of d = 450 mm, determine if the 2.50 m long beam is adequate to carry a uniform load of 15 KN/m and a concentrated load of 10 KN at the cantilever end. Use f’c = 21 MPa, fy = 275 MPa. Neglect the weight of beam. Use n = 9 (Alternate Method of Design) 2. Referring to #1, using the Transformed Section Method, determine if the beam is adequate or not. ...NEED A COMPLETE SOLUTION BASED ON THE NSCP...1. A cantilever R.C. beam is 280 mm x 500 mm deep and is reinforced with 4- 20 mm diam bars for tension. Using an effective depth of d = 450 mm, determine if the 2.50 m long beam is adequate to carry a uniform load of 15 KN/m and a concentrated load of 10 KN at the cantilever end. Use f’c = 21 MPa, fy = 275 MPa. Neglect the weight of beam. Use n = 9 (Alternate Method of Design) Question: Referring to #1, using the same data, determine if the cantilever beam is adequate based on strength design 2001 NSCP specifications. The 15 KN/m load is DL while the 10KN load is LL.
- 1. A cantilever R.C. beam is 280 mm x 500 mm deep and is reinforced with 4- 20 mm diam bars for tension. Using an effective depth of d = 450 mm, determine if the 2.50 m long beam is adequate to carry a uniform load of 15 KN/m and a concentrated load of 10 KN at the cantilever end. Use f’c = 21 MPa, fy = 275 MPa. Neglect the weight of beam. Use n = 9 (Alternate Method of Design)The reinforced beam with a 20-ft span shown in Figure P16.4 is subjected to a dead load of 1 k/ft (excluding beam weight) and a live load of 2 k/ft. Is the beam satisfactory to resist the maximum shear force? Use f'c = 3,000 psi and fy = 60,000 psi.A 5.5m simple beam carries a uniform ultimate load Wu. The beam is laterally supported and has compact section. The properties of the section are: rx=105.16mm, ry=22.2mm, Sx=308000mm^3, Sy=35000mm^3, Zx=357000mm^3, Zy=55000mm^3, and Fy=248MPa. Calculate the ultimate load capacity Wu of the beam in KN/m considering flexure. Express your answer in 3 decimal places.
- 1. A cantilever R.C. beam is 280 mm x 500 mm deep and is reinforced with 4- 20 mm diam bars for tension. Using an effective depth of d = 450 mm, determine if the 2.50 m long beam is adequate to carry a uniform load of 15 KN/m and a concentrated load of 10 KN at the cantilever end. Use f’c = 21 MPa, fy = 275 MPa. Neglect the weight of beam. Use n = 9 (Alternate Method of Design) Referring to #1, using the Transformed Section Method, determine of the beam is adequate or not.A cantilever R.C. beam is 280 mm x 500 mm deep and is reinforced with 4- 20 mm diam bars for tension. Using an effective depth of d = 450 mm, determine if the 2.50 m long beam is adequate to carry a uniform load of 15 KN/m and a concentrated load of 10 KN at the cantilever end. Use f’c = 21 MPa, fy = 275 MPa. Neglect the weight of beam. Use n = 9 (Use Transformed section method)A steel beam is made up of a wide flange section whose total depth is 600mm, width of the flange is 300mm, flange thickness of 20mm and moment of inertia Ix = 1.16x109 mm4 . Its web thickness is 10mm and has a simple span of 9m. A 40 kN/m uniform load is loaded throughout its span and 200kN load acting at midspan. Allowable bending stress of the beam is 148.8 MPa. Situation No.1.1 Determine the length of top and bottom reinforcing plates if necessary
- A steel beam is made up of a wide flange section whose total depth is 600mm, width of the flange is 300mm, flange thickness of 20mm and moment of inertia Ix = 1.16x109 mm4 . Its web thickness is 10mm and has a simple span of 9m. A 40 kN/m uniform load is loaded throughout its span and 200kN load acting at midspan. Allowable bending stress of the beam is 148.8 MPa. Situation No. 1 1. Determine the required section modulus without exceeding the allowable bending stress. 2. Determine the section modulus of the wide flange. 3. Determine the width of top and bottom reinforcing plates 12mm thick if necessary. 4. Determine the length of top and bottom reinforcing plates if necessary.A cantilever R.C. beam is 280 mm x 500 mm deep and is reinforced with 4- 20 mm diam bars for tension. Using an effective depth of d = 450 mm, determine if the 2.50 m long beam is adequate to carry a uniform load of 15 KN/m and a concentrated load of 10 KN at the cantilever end in 2 ways. Use f’c = 21 MPa, fy = 275 MPa. Neglect the weight of beam. Use n = 9 (Alternate Method Design).Given the following elements of a T-beam: Flange width bf= 900 mm, Flange thickness t= 1100 mm, Width of web bw= 310 mm, Effective depth d= 460 mm, Concrete strength FC 20.7 MPa, Steel Strength fy=414 MPa. If the beam is reinforced for tension only, determine the following:5. The balanced steel area6. The nominal and ultimate balanced moment capacity7. The maximum steel area8. The nominal maximum moment capacity9. The ultimate maximum moment capacity Please answer asap, Thanks.