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A 2-lb object, that stretches a spring by 1.5 inches, is released with a downward velocity of 32 ft/sec from 1 ft above the equilibrium position. Assume that the mass does not experience any retarding force and the spring motion is not influenced by an external driving force which is a function of time. Assume g=32 ft/s?. If x is the displacement from the equilibrium position in feet, the differential equation that models the system is x"+16x=0 O x"+256x=0 O x"+32x=0 O x"+21.3x=0

A 2-lb object, that stretches a spring by 1.5 inches, is released with a downward velocity of 32 ft/sec from 1 ft above the equilibrium position. Assume that the mass does not experience any retarding force and the spring motion is not influenced by an external driving force which is a function of time. Assume g=32 ft/s?. If x is the displacement from the equilibrium position in feet, the differential equation that models the system is x"+16x=0 O x"+256x=0 O x"+32x=0 O x"+21.3x=0

Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.7: Applications
Problem 18EQ
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A 2-lb object, that stretches a spring by 1.5 inches, is released with a downward velocity of 32 ft/sec from 1 ft above the equilibrium position. Assume that the mass does not experience any retarding force and the spring motion is not influenced by an external driving force which is a function of time. Assume g=32 ft/s?. If x is the displacement from the equilibrium position in feet, the differential equation that models the system is x"+16x=0 O x"+256x=0 O x"+32x=0 O x"+21.3x=0
Transcribed Image Text:A 2-lb object, that stretches a spring by 1.5 inches, is released with a downward velocity of 32 ft/sec from 1 ft above the equilibrium position. Assume that the mass does not experience any retarding force and the spring motion is not influenced by an external driving force which is a function of time. Assume g=32 ft/s?. If x is the displacement from the equilibrium position in feet, the differential equation that models the system is x"+16x=0 O x"+256x=0 O x"+32x=0 O x"+21.3x=0
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