A 200-gal tank is half full of distilled water. At what time (t) = 0, a solution containing 0.5 lb/gal of concentrate enters the tank at the rate of 5 gal/min, and the well-stirred mixture is withdrawn at the rate of 3 gal/min. a. At what time will the tank be full? b. At the time the tank is full, how many pounds of concentrate will it contain?

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.4: Values Of The Trigonometric Functions
Problem 23E
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A 200-gal tank is half full of distilled water. At what time (t) = 0, a solution containing 0.5 lb/gal of concentrate enters the tank at the rate of 5 gal/min, and the well-stirred mixture is withdrawn at the rate of 3 gal/min. a. At what time will the tank be full? b. At the time the tank is full, how many pounds of concentrate will it contain?
y3 (100+a®)+ C (100 +aC0)~3/2
312
CICDCO 312
312
C=- 50-(I0の)
-3/2
y (100+ at) + (-50 - (100") - (100 + Xt)
-3/2
3/2
%3D
312
y= (100 + a(50)+ (-50 (10)
3/2
(100+a(5の0)
y= 200 - 50(uoco)
312
a(a00) 32
312
= a0c0 - 50(KO0)
2(200) 3/2
y = 191. 16 lb al concentretion
Transcribed Image Text:y3 (100+a®)+ C (100 +aC0)~3/2 312 CICDCO 312 312 C=- 50-(I0の) -3/2 y (100+ at) + (-50 - (100") - (100 + Xt) -3/2 3/2 %3D 312 y= (100 + a(50)+ (-50 (10) 3/2 (100+a(5の0) y= 200 - 50(uoco) 312 a(a00) 32 312 = a0c0 - 50(KO0) 2(200) 3/2 y = 191. 16 lb al concentretion
7.3 #2
Sgaldmin
Integrating Fackor
0.5 Ib/gal
pal) +
dt du = a.dt
dt 1. du
%3D
e
3gal
D wotat
3 gall/Nin
3.
In (100+2t)
In (100+at) oe (100+at)
WHAT WakNew
3/2
yCt)
DepaftuRE rate =
V(t)
(out flow reate)
%3D
2
312
3 gal /min
t (rate in- rate out)
3gal/min
5 (100+2t)
2.
STEP 3:
Stop. 1
3/2 dy +
100 +
(100+at)
de
100 + 2t
conentratxn
out
3/2
3/2
1/2
y(t) = 3gal/min Cy)ct)
V(E)
(100 -2€)
4 (100+at)+ 3(100+at)'*.y=
2.
dt
roo + at
f
3/2
((00+at)
3/2
step 2.
dy - (chamical's anrival rete)-
dt
y(t)
(outflow rate)
d 100+ at)
dt
3/2
S (100+at) . de
%3D
cancels out
fate in 0,5 lb/gal) (5.Øgal/min)
Iblgal - 5,0 gal /min
才
%3D
U=100+ 2t
du= a.dt dt =du
5.
2J MOVADAH (u).. du
dxt
%3D
3/2
%3D
"Cherical = 5 1b /min
2
3/2
du
2
2 2
516/min --3gal / min
2.
dt
dy
3/2
%3D
(00 + 24
(100+a+)
5/2
(lo0tat)
ntegrating
Factor
dy + 3gal /min
STEP, 4: Find C,
wo +Qt
Find C when inrtial t=0
continue
11
Transcribed Image Text:7.3 #2 Sgaldmin Integrating Fackor 0.5 Ib/gal pal) + dt du = a.dt dt 1. du %3D e 3gal D wotat 3 gall/Nin 3. In (100+2t) In (100+at) oe (100+at) WHAT WakNew 3/2 yCt) DepaftuRE rate = V(t) (out flow reate) %3D 2 312 3 gal /min t (rate in- rate out) 3gal/min 5 (100+2t) 2. STEP 3: Stop. 1 3/2 dy + 100 + (100+at) de 100 + 2t conentratxn out 3/2 3/2 1/2 y(t) = 3gal/min Cy)ct) V(E) (100 -2€) 4 (100+at)+ 3(100+at)'*.y= 2. dt roo + at f 3/2 ((00+at) 3/2 step 2. dy - (chamical's anrival rete)- dt y(t) (outflow rate) d 100+ at) dt 3/2 S (100+at) . de %3D cancels out fate in 0,5 lb/gal) (5.Øgal/min) Iblgal - 5,0 gal /min 才 %3D U=100+ 2t du= a.dt dt =du 5. 2J MOVADAH (u).. du dxt %3D 3/2 %3D "Cherical = 5 1b /min 2 3/2 du 2 2 2 516/min --3gal / min 2. dt dy 3/2 %3D (00 + 24 (100+a+) 5/2 (lo0tat) ntegrating Factor dy + 3gal /min STEP, 4: Find C, wo +Qt Find C when inrtial t=0 continue 11
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