A 220V, 900rpm, 120A separately excited dc motor has an armature resistance of 0.05 Q. It is fed from a single phase fully -controlled converter with an a.c source voltage of 240 V , 50 Hz, Assuming continuous conduction mode of operation, Calculate (i) Find the speed of the motor when firing angle of the converter is 45 degree and motor is operating at rated torque (ii) Find the speed of the motor firing angle of the converter is 140 degree andand motor is operating at rated torque
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- Design 10 HP, 440 V, 3-Phase, 4-pole, 50 Hz squirrel cage induction motor which is be started using a star-delta starter. Find the main dimensions, number of turns per phase & numbe stator slots. Assume:-Average flux density in the gap = 0.45wb/m², Ampere conductors per meter = 2300 ,Efficiency =0.85Power factor = 0.84, stator winding factor = 0.955. Choose the main dimension to p an overall good design.A 440V, 50 Hz, 6 pole, Y-connected induction motor is rated at 75 kW. The equivalent circuit parameters are R1 Ω =0.082 Ω R2 = 0.070 Ω XM = 7.2 Ω X1 Ω =0.19 Ω X2 = 0.180 Ω In this problem, you are to calculate the pull-out torque. The slip is 0.04. a) Rth and Vth? b) Slip at pullout torque Smax? c) The pullout torque Tmax?A 440V, 60Hz, 10 pole delta connected induction motor is rated at 100KW. The equivalent parameter for the motor are: Rs = 0.15 Ω R2` = 0.15 Ω Xs = 0.3 Ω X2` = 0.2 Ω Xm = 6 Ω R c = 120 Ω At full load condition, the friction and windage losses are 600W. The slip of the motor is 0.04. Calculate: The stator line current Is ? The input power ? Stator copper losses ? The air gap power PG ? The converted power Pconv? The torque induced by the motor ? The load torque ? The starting torque? The efficiency of the motor ?
- A 110-V, 1-phase, 4-pole, 60-Hz induction motor has the following circuit constants: R1 = R2’ = 1.6 ohm,X1 = X2’ = 1.8 ohm, Xm = 60 ohm; core loss is 16 W and friction and windage loss is 12 W. Determine theefficiency of the motor at 0.04 slip by using (a) the exact equivalent circuit and (b) the approximateequivalent circuitA factory is to replace 42 identical conventional three‐phase induction motors with the same rating and number more efficient induction motors. Evaluate the value of power taken from the factory supply by the all 42 new motors. The information for the new motors as supplied by the manufactures is: 40 kW, 4‐pole, 1440 rev/min 50‐Hz, Y‐, friction and windage torque of 24 N.m on the shaft. The stator losses are equal to the rotor circuit losses. Assume full‐load output at rated speed. Determine the efficiency of each new motor.The equivalent circuit parameters of a 230-V, 1-phase, 6-pole, 60-Hz induction motor are: R1 = R2’ =10 ohms, X1 = X2’ = 10 ohms, and Xm = 100 ohms. At a slip of 5%, calculate (a) motor speed, (b) input current, (c)power factor, (d) developed torque. (e) at 230V, while running on no-load, is 31.4 W at 1.2 A.What is the approximate efficiency of the motor at 5% slip?
- 381 V, four pole, 50 Hz, Y connected, to an asynchronous motor with a nominal power of 13.8 HP The corresponding equivalent circuit parameters are given below. R 1 = 0.15 Ω, R′2 = 0.154 Ω, Xm = 20 Ω, X′σ1 = 0.852 Ω, X′σ2 = 1.066 Ω It is calculated as Pstme = 390 W and Piron = 600 W for operation at label values. There is a load moment of 34 Nm on the motor shaft. Accordingly, the friction loss remains constant; a. The power transferred to the load when the motor is fed with a voltage of 50 Hz 4.16 is kW I. Draw the simplified T-equivalent circuit, not given in the circuit Calculate if there are parameters. ii. Calculate the phase current and phase voltage for the given operating condition. iii. Calculate the efficiency of the engine. iv. Calculate the tipping moment and tipping slip.A 3-phase, 440-V, delta-connected, 4-pole 50-Hz induction motor runs at a speed of 1447 rpm when operating at its rated load. The equivalent circuit has the following per-phase :parametersr1=0.2 Ω, x1=x2'=2 Ω , r2'=0.4 Ω, rc=200 Ω , xɸ = 40 Ω Using the approximate circuit, determine, for rated load, the values of line current and power factor, torque, output power and efficiency. The mechanical loss is 1000 watts.A four-pole, three-phase induction motor rotatesat 1,700 r/min when the load is 100 N-m. The motoris 88 percent efficient.a. Determine the slip at this operating condition.b. For a constant-power, 10-kW load, determine theoperating speed of the machine.c. Sketch the motor and load torque–speed curves onthe same graph. Show numerical values.d. What is the total power consumed by themotor?
- A three - phase, 460V, 60HZ, 4 - pole Y - connected induction motor has the following equivalent circuit parameters: Rs = 0.420, R = 0.230, X, = X =0.820, and Xm = 220. The no - load loss Pioss = 60W, assumed as a constant. The rotor speed is 1750 rpm. Determine (i) the developed power, and (ii) the efficiencyA 4-pole ,400 V, 50 Hz wound-rotor induction motor has the following circuit model parameters: R = 0.3 2, R2 = 0.25 2, X X2' 0.6 2, Xo 35 2 and rotational loss of 1500 W ( Ro is negligible). When the motor running at 1425 rpm, %3D %3D %3D %3D calculate a) the motor efficiency and, b) the maximum gross power when exciting circuit is omitted.Three-phase induction motor, 460 V 50 Hz, 4 poles, 50 hp with Delta, operating at 3.8% slip rated torque when receives Line Voltage 460 V, 50 Hz The parameters of the equivalent circuit per phase are as follows.R1 = 0.33, X1 = X2 = 0.42 and Xm = 30 Ohm / phase.Answer the following questions by neglecting the mechanical losses, Core losses and Stray load losses.A) Value of the rotor resistance R2 B) Maximum torque and rated speed C) line current and starting torque of motor