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A 3 m wide rectangular channel, as shown, carries a flow of 11.7m³/s. hydraulic jump Ус y2 2 Az = 0.4m 3 At section 3, it is observed that the flow profile goes through a critical depth control above the 0.4m step in the channel base. a) Calculate the critical energy at section 3. b) Assuming there is no energy loss between section 2 and 3, use the energy equation to show that the depth y2, at O, is approximately equal to 1.927 m. Just upstream of section 2, a hydraulic jump forms. Use the hydraulic jump formula to calculate the depth y1, at O

A 3 m wide rectangular channel, as shown, carries a flow of 11.7m³/s. hydraulic jump Ус y2 2 Az = 0.4m 3 At section 3, it is observed that the flow profile goes through a critical depth control above the 0.4m step in the channel base. a) Calculate the critical energy at section 3. b) Assuming there is no energy loss between section 2 and 3, use the energy equation to show that the depth y2, at O, is approximately equal to 1.927 m. Just upstream of section 2, a hydraulic jump forms. Use the hydraulic jump formula to calculate the depth y1, at O

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A 3 m wide rectangular channel, as shown, carries a flow of 11.7m/s. hydraulic jump Ус y2 y1 Az = 0.4m 3 At section 3, it is observed that the flow profile goes through a critical depth control above the 0.4m step in the channel base. a) Calculate the critical energy at section 3. b) Assuming there is no energy loss between section 2 and 3, use the energy equation to show that the depth y2, at 2, is approximately equal to 1.927 m. Just upstream of section (2, a hydraulic jump forms. Use the hydraulic jump formula to calculate the depth y1, at O
Transcribed Image Text:A 3 m wide rectangular channel, as shown, carries a flow of 11.7m/s. hydraulic jump Ус y2 y1 Az = 0.4m 3 At section 3, it is observed that the flow profile goes through a critical depth control above the 0.4m step in the channel base. a) Calculate the critical energy at section 3. b) Assuming there is no energy loss between section 2 and 3, use the energy equation to show that the depth y2, at 2, is approximately equal to 1.927 m. Just upstream of section (2, a hydraulic jump forms. Use the hydraulic jump formula to calculate the depth y1, at O
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