A 4-pound weight stretches a spring 2 feet. The weight is released from rest 20 inches above the equilibrium position, and the resulting motion takes place in a medium offering a damping force numerically equal to times the instantaneous velocity. Use the Laplace transform to find the equation of motion x(t). (Use g = 32 ft/s² for the acceleration due to gravity.) x(t): = 5-(²¹) cos( √15+) 2 35 3√/ 15 -(-²). e √15 t sin 151 2

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A 4-pound weight stretches a spring 2 feet. The weight is released from rest 20 inches above the equilibrium position, and
the resulting motion takes place in a medium offering a damping force numerically equal to times the instantaneous
velocity. Use the Laplace transform to find the equation of motion x(t). (Use g = 32 ft/s² for the acceleration due to
gravity.)
x(t) =
5
-se (31)
3
COS
15 t
2
35 - (-/-/-)
e
3√15
sin
√15 t
2
Transcribed Image Text:A 4-pound weight stretches a spring 2 feet. The weight is released from rest 20 inches above the equilibrium position, and the resulting motion takes place in a medium offering a damping force numerically equal to times the instantaneous velocity. Use the Laplace transform to find the equation of motion x(t). (Use g = 32 ft/s² for the acceleration due to gravity.) x(t) = 5 -se (31) 3 COS 15 t 2 35 - (-/-/-) e 3√15 sin √15 t 2
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