
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN: 9781259696527
Author: J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher: McGraw-Hill Education
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A 4-in. schedule 80 steel pipe (ID = 3.826 in., OD = 4.5 in.) carries a heat-transfer fluid at 600 F and is covered with a 1/2 -in. thick layer of pipe insulation. The pipe is surrounded by air at 80 F. The vendor’s literature states that a 1-in. thick layer of the pipe insulation has an R-value of 3. Neglecting convective resistances, the resistance of the pipe wall, and thermal radiation, estimate the rate of heat loss from the pipe per foot of length.
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- 2. The wall of a furnace is made up of a material which has thermal conductivity of 1.65 W/m•C and a thicknesses 250 mm. The inner side of the furnace wall is exposed to hot gases at 1000 °C with a convection coefficient of 25 W/m2°C and the inside the surface is at 800 °C. The air outside the furnace is at 25°C with a convection coefficient of 12 W/m2°C. a. Draw a clear diagram representing the system b. Determine the temperature of the outside surface of the furnace C. The rate of heat loss from the furnace.arrow_forwardExample • The cylinder is made from aluminum with diameter and thickness of 5 cm and 1 cm respectively. The wall temperature in the inside of cylinder is 50°C, while the temperature of the air is 30°C. the coefficient of convection in the air is 10 W/m2-C. Calculate the heat loss from the cylinder per unit length! • Calculate the thickness of the insulation so heat loss from cylinder will decrease 50% of initial condition. Thermal conductivity of the isolator (k) : 0.5 W/m°C state.pptx 7 MB VIEW Tampilkan semuaarrow_forwardQ3) A fused-quartz sphere has a thermal diffusivity of 9.5 x 107 m²/s, a diameter of 2.5 cm, and a thermal conductivity of 1.52 W/m. °C. The sphere is initially at a uniform temperature of 25 °C and is suddenly subjected to a convection environment at 250 °C. The convection heat-transfer coefficient is 110 W/m². °C. Calculate the temperatures at the center and at a radius of 5 mm after a time of 8 min.arrow_forward
- .240mm steam main pipe, 210m long is covered with 50mm of high temperature insulation (k-0.092 W/m °C) and 40mm of low temperature insulation (k-0.062 W/m °C). The inner and the outer surface temperature as measured are 390 °C and 40 °C respectively. Calculate: 1- The total heat loss per hour. 2- The temperature between two layers of insulation.arrow_forwardIn a multi-layered square wall, the thermal resistance of the first layer is 0.005 ° C / W, the resistance of the second layer is 0.4 ° C / W, and the third layer is 0.1 ° C / W. The overall temperature gradient in the wall is multilayered from one side. to the other side is 60 ° C. a. Determine the heat flux through the walls. = Answerwatts / m2. b. If the thermal resistance of the second layer is changed to 0.2 ° C / W, what is the effect in% on heat flux, assuming the temperature gradient remains the same? = %. Answerarrow_forwardIn a multi-layered square wall, the thermal resistance of the first layer is 0.005 ° C / W, the resistance of the second layer is 0.4 ° C / W, and the third layer is 0.1 ° C / W. The overall temperature gradient in the wall is multilayered from one side. to the other side is 60 ° C. a. Determine the heat flux through the walls. = Answerwatt / m2. b. If the thermal resistance of the second layer is changed to 0.2 ° C / W, what is the effect in% on heat flux, assuming the temperature gradient remains the same? = AnswerAnswer%.arrow_forward
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